exercise_issues#3.ipynb

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 "cells": [
  {
   "cell_type": "code",
   "execution_count": 27,
   "id": "d4e21ba5",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "#fff\n"
     ]
    }
   ],
   "source": [
    "#Exercise1\n",
    "x = [1,'Hello', True, 1.093E-3,'#fff']\n",
    "print(x[-1])"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 28,
   "id": "e7dc6ba6",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "4\n",
      "1\n",
      "4\n",
      "5\n"
     ]
    }
   ],
   "source": [
    "#Exercise2\n",
    "x = [9, 3, 4, 1, 4, 5, 6, 3, 7, 8]\n",
    "for i in x[2:6]:\n",
    "    print(i)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 29,
   "id": "040f3431",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "1\n",
      "  2\n",
      "    3\n",
      "  4\n",
      "    5\n",
      "      6\n",
      "  7\n",
      "8\n"
     ]
    }
   ],
   "source": [
    "#Exercise3\n",
    "x = [1,[2,[3],4,[5,[6]]],[7],8]\n",
    "    \n",
    "\n",
    "for i in x:\n",
    "    if isinstance(i, list):\n",
    "        for j in i:\n",
    "            if isinstance(j, list):\n",
    "                for k in j:\n",
    "                    if isinstance(k, list):\n",
    "                        for b in k:\n",
    "                            print('     ',b)\n",
    "                    else:\n",
    "                        print('   ',k)\n",
    "            else:\n",
    "                print(' ', j)\n",
    "    else:\n",
    "        print(i)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 32,
   "id": "2396f32b",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "x: [1, 3, 4, 5]\n",
      "y: ['a', 2, 'b', 'c']\n",
      "z: [1, 3, 4, 5, 'a', 2, 'b', 'c']\n"
     ]
    }
   ],
   "source": [
    "#Exercise4\n",
    "x = [1, 2, 3, 4, 5]\n",
    "y = ['a', 'b', 'c']\n",
    "z = x.pop(1)\n",
    "y.insert(1, z)\n",
    "z = x + y\n",
    "\n",
    "print(\"x:\", x)\n",
    "print(\"y:\", y)\n",
    "print(\"z:\", z)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 34,
   "id": "c4dce294",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "['a', 2000, 'i', 'o', 'u']\n",
      "['a', 'e', 'i', 'o', 'u']\n"
     ]
    }
   ],
   "source": [
    "#Exercise5\n",
    "a = 'aeiou'\n",
    "b = tuple(a)\n",
    "c = list(b)\n",
    "d = c\n",
    "e = list(d)\n",
    "c[1] = 2000\n",
    "print(d)\n",
    "print(e)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 35,
   "id": "72612dbe",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[0, 1, 2, 3, 4, 5]\n",
      "[2, 4, 3, 1, 0, 5]\n",
      "[5, 4, 3, 2, 1, 0]\n",
      "[5, 4, 3, 2, 1, 0]\n"
     ]
    }
   ],
   "source": [
    "#Exercise6\n",
    "#To get [0, 1, 2, 3, 4, 5]\n",
    "result1 = sorted([5, 0, 1, 3, 4, 2])\n",
    "print(result1)\n",
    "\n",
    "#To get [2, 4, 3, 1, 0, 5]\n",
    "result2 = [5, 0, 1, 3, 4, 2][::-1]\n",
    "print(result2)\n",
    "\n",
    "#To get [5, 4, 3, 2, 1, 0]\n",
    "result3 = sorted([5, 0, 1, 3, 4, 2], reverse=True)\n",
    "print(result3)\n",
    "\n",
    "#To get [5, 4, 3, 2, 1, 0] in two lines\n",
    "original_list = [5, 0, 1, 3, 4, 2]\n",
    "result4 = list(reversed(sorted(original_list)))\n",
    "print(result4)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 36,
   "id": "6992bf05",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "count of 1: 4\n",
      "\n",
      "1st index of 1: 1\n",
      "\n",
      "2nd index of 1: 2\n"
     ]
    }
   ],
   "source": [
    "x = [0, 1, 2, 3, 1, 4, 5, 6, 1, 9, 9, 1]\n",
    "\n",
    "print('count of 1:', x.count(1))\n",
    "print()\n",
    "\n",
    "c0 = x.index(1)\n",
    "print('1st index of 1:', c0)\n",
    "print()\n",
    "\n",
    "c1 = x[c0 + 1:].index(1)\n",
    "print('2nd index of 1:', c1)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 40,
   "id": "cc1be832",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[0, 2, 4]\n",
      "[1, 3, 5]\n",
      "[1, 3, 5, 3, 5, 7, 5, 7, 9]\n"
     ]
    }
   ],
   "source": [
    "#Exercise8\n",
    "x = [i for i in range (0,5,2)]\n",
    "y = [i for i in range (1,6,2)]\n",
    "z = [i+j for i in x for j in y]\n",
    "\n",
    "print(x)\n",
    "print(y)\n",
    "print(z)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 42,
   "id": "fb1b3bfb",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "original\n",
      "[1, 5, 2, 4, 3] \n",
      "\n",
      "after modified bubble sort\n",
      "[5, 1, 2, 3, 4]\n"
     ]
    }
   ],
   "source": [
    "#Exercise9\n",
    "x = [1, 5, 2, 4, 3]\n",
    "\n",
    "print('original')\n",
    "print(x, '\\n')\n",
    "\n",
    "N = len(x)\n",
    "\n",
    "for i in range(N):\n",
    "    for j in range(1, N):\n",
    "        if x[i] < x[j]:\n",
    "            x[i], x[j] = x[j], x[i]\n",
    "\n",
    "print('after modified bubble sort')\n",
    "print(x)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 43,
   "id": "1b6e187f",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "['a', 1, 'b', 2, 'c', 3] \n",
      "\n",
      "['a', 'b', 'c'] \n",
      "\n",
      "[1, 2, 3]\n"
     ]
    }
   ],
   "source": [
    "#Exercise10\n",
    "def sep_odd_even_index(z):\n",
    "    N = len(z)\n",
    "    r = range(N)\n",
    "    x = [z[i] for i in r if i % 2 == 0]\n",
    "    y = [z[i] for i in r if i % 2 == 1]\n",
    "    return x, y\n",
    "\n",
    "mix = ['a', 1, 'b', 2, 'c', 3]\n",
    "x, y = sep_odd_even_index(mix)\n",
    "\n",
    "print(mix, '\\n')\n",
    "print(x, '\\n')\n",
    "print(y)\n",
    "#Purpose of sep_odd_even_index function:\n",
    "#The function takes a list z as input and separates its elements into two lists (x and y)\n",
    "#The elements at even indices (starting from 0) are placed in the list x\n",
    "#and the elements at odd indices are placed in the list y."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "168306f8",
   "metadata": {},
   "outputs": [],
   "source": []
  }
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