Exercise3.ipynb

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   "source": [
    "# Mazam Ganendra\n",
    "# NIT 21181192\n",
    "# Lecture 19-Feb-2024, Session 3 Review and Mastering Python List for Data Science #3"
   ]
  },
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   "cell_type": "code",
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   "id": "0d6b4d4c",
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     "text": [
      "#fff\n"
     ]
    }
   ],
   "source": [
    "# Exercise 1\n",
    "x = [1,'Hello', True, 1.093E-3,'#fff']\n",
    "\n",
    "print(x[-1])"
   ]
  },
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   "execution_count": 7,
   "id": "a5bdce12",
   "metadata": {},
   "outputs": [
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     "text": [
      "4\n",
      "1\n",
      "4\n",
      "5\n"
     ]
    }
   ],
   "source": [
    "# Exercise 2\n",
    "x = [9, 3, 4, 1, 4, 5, 6, 3, 7, 8]\n",
    "\n",
    "for i in x[2:6]:\n",
    "    print(i)"
   ]
  },
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   "cell_type": "code",
   "execution_count": 8,
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     "text": [
      "1\n",
      "   2\n",
      "     3\n",
      "   4\n",
      "     5\n",
      "       6\n",
      "   7\n",
      "8\n"
     ]
    }
   ],
   "source": [
    "# Exercise 3\n",
    "x = [1, [2, [3], 4, [5, [6]], 7], 8]\n",
    "for i in x:\n",
    "    if isinstance(i, list):\n",
    "        for j in i:\n",
    "            if isinstance(j, list):\n",
    "                for k in j:\n",
    "                    if isinstance(k, list):\n",
    "                        for l in k:\n",
    "                            print('      ', l)\n",
    "                    else:\n",
    "                        print('    ', k)\n",
    "            else:\n",
    "                print('  ', j)\n",
    "    else:\n",
    "        print(i)"
   ]
  },
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   "cell_type": "code",
   "execution_count": 9,
   "id": "e8d732a8",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[1, 3, 4, 5]\n",
      "['a', 2, 'b', 'c']\n",
      "[1, 3, 4, 5, 'a', 2, 'b', 'c']\n"
     ]
    }
   ],
   "source": [
    "# Exercise 4\n",
    "x = [1, 2, 3, 4, 5]\n",
    "y = ['a', 'b', 'c']\n",
    "z = x.pop(1)\n",
    "y.insert(1,z)\n",
    "z = x + y\n",
    "\n",
    "print(x)\n",
    "print(y)\n",
    "print(z)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 10,
   "id": "8f3ddf0f",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "['a', 2000, 'i', 'o', 'u']\n",
      "['a', 'e', 'i', 'o', 'u']\n"
     ]
    }
   ],
   "source": [
    "# Exercise 5\n",
    "a = 'aeiou'\n",
    "b = tuple(a)\n",
    "c = list(b)\n",
    "d = c\n",
    "e = list(d)\n",
    "\n",
    "c[1] = 2000\n",
    "print(d)\n",
    "print(e)"
   ]
  },
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   "cell_type": "code",
   "execution_count": 1,
   "id": "1a45c2c6",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[0, 1, 2, 3, 4, 5]\n",
      "[2, 4, 3, 1, 0, 5]\n",
      "[5, 4, 3, 2, 1, 0]\n",
      "[5, 4, 3, 2, 1, 0]\n"
     ]
    }
   ],
   "source": [
    "# Exercise 6\n",
    "#To get [0, 1, 2, 3, 4, 5]\n",
    "result1 = sorted([5, 0, 1, 3, 4, 2])\n",
    "print(result1)\n",
    "\n",
    "#To get [2, 4, 3, 1, 0, 5]\n",
    "result2 = [5, 0, 1, 3, 4, 2][::-1]\n",
    "print(result2)\n",
    "\n",
    "#To get [5, 4, 3, 2, 1, 0]\n",
    "result3 = sorted([5, 0, 1, 3, 4, 2], reverse=True)\n",
    "print(result3)\n",
    "\n",
    "#To get [5, 4, 3, 2, 1, 0] in two lines\n",
    "original_list = [5, 0, 1, 3, 4, 2]\n",
    "result4 = list(reversed(sorted(original_list)))\n",
    "print(result4)\n"
   ]
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   "execution_count": 2,
   "id": "2eef560a",
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   "outputs": [
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     "name": "stdout",
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     "text": [
      "count of 1: 4\n",
      "\n",
      "1st index of 1: 1\n",
      "2nd index of 1: 2\n"
     ]
    }
   ],
   "source": [
    "# Exercise 7\n",
    "x = [0, 1, 2, 3, 1, 4, 5, 6, 1, 9, 9, 1]\n",
    "print('count of 1:', x.count(1))\n",
    "print()\n",
    "\n",
    "c0 = x.index(1)\n",
    "print('1st index of 1:', c0)\n",
    "\n",
    "c1 = x[c0 + 1:].index(1)\n",
    "print('2nd index of 1:', c1)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 3,
   "id": "831373e4",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[0, 2, 4]\n",
      "[1, 3, 5]\n",
      "[2, 4, 6, 2, 4, 6, 2, 4, 6]\n"
     ]
    }
   ],
   "source": [
    "# Exercise 8\n",
    "x = [i for i in range(0, 5, 2)]\n",
    "y = [i for i in range(1, 6, 2)]\n",
    "z = [1+j for i in x for j in y]\n",
    "\n",
    "print(x)\n",
    "print(y)\n",
    "print(z)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 5,
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   "metadata": {},
   "outputs": [
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     "text": [
      "original\n",
      "[1, 5, 2, 4, 3] \n",
      "\n",
      "after modified bubble sort\n",
      "[5, 1, 2, 3, 4]\n"
     ]
    }
   ],
   "source": [
    "# Exercise 9\n",
    "x = [1, 5, 2, 4, 3]\n",
    "\n",
    "print('original')\n",
    "print(x, '\\n')\n",
    "\n",
    "N = len(x)\n",
    "\n",
    "for i in range(N):\n",
    "    for j in range(1, N):\n",
    "        if x[i] < x[j]:\n",
    "            x[i], x[j] = x[j], x[i]\n",
    "\n",
    "print('after modified bubble sort')\n",
    "print(x)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 6,
   "id": "d3830396",
   "metadata": {},
   "outputs": [
    {
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     "output_type": "stream",
     "text": [
      "['a', 1, 'b', 2, 'c', 3] \n",
      "\n",
      "['a', 'b', 'c'] \n",
      "\n",
      "[1, 2, 3]\n"
     ]
    }
   ],
   "source": [
    "# Exercise 10\n",
    "def sep_odd_even_index(z):\n",
    "    N = len(z)\n",
    "    r = range(N)\n",
    "    x = [z[i] for i in r if i % 2 == 0]\n",
    "    y = [z[i] for i in r if i % 2 == 1]\n",
    "    return [x, y]\n",
    "\n",
    "mix = ['a', 1, 'b', 2, 'c', 3]\n",
    "x, y = sep_odd_even_index(mix)\n",
    "print(mix, '\\n')\n",
    "print(x, '\\n')\n",
    "print(y)"
   ]
  }
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