ISSUES3.ipynb

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     "text": [
      "#fff\n"
     ]
    }
   ],
   "source": [
    "#EXERCISE_1\n",
    "x = [1, 'Hello', True, 1.093E-3, '#fff']\n",
    "print(x[-1])"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 7,
   "id": "539e71f9",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "4\n",
      "1\n",
      "4\n",
      "5\n"
     ]
    }
   ],
   "source": [
    "#EXERCISE_2\n",
    "x = [9, 3, 4, 1, 4, 5, 6, 3, 7, 8]\n",
    "for i in x[2:6]:\n",
    "    print(i)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 21,
   "id": "6b9e0737",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "1\n",
      "  2\n",
      "    3\n",
      "  4\n",
      "    5\n",
      "      6\n",
      "  7\n",
      "8\n"
     ]
    }
   ],
   "source": [
    "#EXERCISE_3\n",
    "x = [1, [2, [3], 4,[5]], [[[6]]], [7], 8]\n",
    "for i in x:\n",
    "    if isinstance(i, list):\n",
    "        for j in i:\n",
    "            if isinstance(j, list):\n",
    "                for k in j:\n",
    "                    if isinstance(k, list):\n",
    "                        for y in k:\n",
    "                            print('     ', y)\n",
    "                    else:\n",
    "                        print('   ', k)\n",
    "            else:\n",
    "                print(' ', j)\n",
    "    else:\n",
    "        print(i)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 22,
   "id": "aa877182",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[1, 3, 4, 5]\n",
      "['a', 2, 'b', 'c']\n",
      "[1, 3, 4, 5, 'a', 2, 'b', 'c']\n"
     ]
    }
   ],
   "source": [
    "#EXERCISE_4\n",
    "x = [1, 2, 3, 4, 5]\n",
    "y = ['a', 'b', 'c']\n",
    "z = x.pop(1)\n",
    "y.insert(1, z)\n",
    "z = x + y\n",
    "\n",
    "print(x)\n",
    "print(y)\n",
    "print(z)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 23,
   "id": "d801f921",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "['a', 2000, 'i', 'o', 'u']\n",
      "['a', 'e', 'i', 'o', 'u']\n"
     ]
    }
   ],
   "source": [
    "#EXERCISE_5\n",
    "a = 'aeiou'\n",
    "b = tuple(a)\n",
    "c = list(b)\n",
    "d = c\n",
    "e = list(d)\n",
    "\n",
    "c[1] = 2000\n",
    "print(d)\n",
    "print(e)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 28,
   "id": "cffcb393",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[0, 1, 2, 3, 4, 5]\n",
      "[2, 4, 3, 1, 0, 5]\n",
      "[5, 4, 3, 2, 1, 0]\n",
      "[5, 4, 3, 2, 1, 0]\n"
     ]
    }
   ],
   "source": [
    "#EXERCISE_6\n",
    "#To get [0, 1, 2, 3, 4, 5]\n",
    "x = sorted ([5, 0, 1, 3, 4, 2])\n",
    "print(x)\n",
    "\n",
    "#To get [2, 4, 3, 1, 0, 5]\n",
    "y = [5, 0, 1, 3, 4, 2][::-1]\n",
    "print(y)\n",
    "\n",
    "#To get [5, 4, 3, 2, 1, 0]\n",
    "z = sorted([5, 0, 1, 3, 4, 2], reverse=True)\n",
    "print(z)\n",
    "\n",
    "#To get [5, 4, 3, 2, 1, 0] in two lines\n",
    "zz = [5, 0, 1, 3, 4, 2]\n",
    "yz = list(reversed(sorted(zz)))\n",
    "print(yz)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 37,
   "id": "9dd5488b",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "count of 1: 4\n",
      "\n",
      "1st index of 1: 1\n",
      "\n",
      "2nd index of 1: 4\n",
      "\n"
     ]
    }
   ],
   "source": [
    "#EXERCISE_7\n",
    "x = [0, 1, 2, 3, 1, 4, 5, 6, 1, 9, 9, 1]\n",
    "\n",
    "print('count of 1:', x.count(1))\n",
    "print()\n",
    "\n",
    "c0 = x.index(1)\n",
    "print('1st index of 1:', c0)\n",
    "print()\n",
    "\n",
    "#wrongsyntax=c1 = x[c0 + 1:].index(1)\n",
    "#correction=\n",
    "c1 = x.index(1,c0 + 1)\n",
    "print('2nd index of 1:', c1)\n",
    "print()"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 38,
   "id": "2655c8eb",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[0, 2, 4]\n",
      "[1, 3, 5]\n",
      "[1, 3, 5, 3, 5, 7, 5, 7, 9]\n"
     ]
    }
   ],
   "source": [
    "#EXERCISE_8\n",
    "x = [i for i in range (0,5,2)]\n",
    "y = [i for i in range (1,6,2)]\n",
    "z = [i+j for i in x for j in y]\n",
    "\n",
    "print(x)\n",
    "print(y)\n",
    "print(z)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 42,
   "id": "73d29450",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "original\n",
      "[1, 5, 2, 4, 3] \n",
      "\n",
      "after modified descending bubble sort\n",
      "[5, 4, 3, 2, 1]\n"
     ]
    }
   ],
   "source": [
    "#EXERCISE_9\n",
    "x = [1, 5, 2, 4, 3]\n",
    "\n",
    "print('original'); print(x, '\\n')\n",
    "\n",
    "N = len(x)\n",
    "\n",
    "for i in range(N):\n",
    "    for j in range(i+1, N):\n",
    "        if x[i] < x[j]:\n",
    "            x[i], x[j] = x[j], x[i]\n",
    "\n",
    "print('after modified descending bubble sort'); print(x)\n"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 46,
   "id": "6df7b6b4",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "['a', 1, 'b', 2, 'c', 3] \n",
      "\n",
      "['a', 'b', 'c'] \n",
      "\n",
      "[1, 2, 3]\n"
     ]
    }
   ],
   "source": [
    "#EXERCISE_10\n",
    "def sep_odd_even_index(z):\n",
    "    N = len(z)\n",
    "    r = range(N)\n",
    "    x = [z[i] for i in r if i % 2 == 0]\n",
    "    y = [z[i] for i in r if i % 2 == 1]\n",
    "    return [x, y]\n",
    "\n",
    "mix = ['a', 1, 'b', 2, 'c', 3]\n",
    "x, y = sep_odd_even_index(mix)\n",
    "print(mix, '\\n')\n",
    "print(x, '\\n')\n",
    "print(y)\n",
    "\n",
    "#The purpose of the sep_odd_even_index function is to separate the elements of a list into two sublists based on their indices (even and odd). Heres a breakdown of how it works:\n",
    "#      1. Input:\n",
    "#          The function takes a single argument z, which is the list to be separated.\n",
    "#      2. Steps:\n",
    "#          Calculate list length: The function first calculates the length of the input list z and stores it in the variable N.\n",
    "#            Generate index range: It creates a range of numbers from 0 to N-1 using range(N). This range represents the indices of the elements in the list.\n",
    "#              Separate elements based on even/odd indices:\n",
    "#          The function uses list comprehension to create two sublists:\n",
    "#              x: This sublist contains elements from the original list z at even indices (0, 2, 4, ...). The condition i % 2 == 0 in the list comprehension filters the indices to select only even numbers.\n",
    "#              y: This sublist contains elements from the original list z at odd indices (1, 3, 5, ...). The condition i % 2 == 1 selects only odd indices.\n",
    "#          Return: The function returns a list containing the two sublists x and y.\n",
    "#            the output will be :\n",
    "#            ['a', 1, 'b', 2, 'c', 3] \n",
    "#            ['a', 'b', 'c'] \n",
    "#            [1, 2, 3]"
   ]
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   "execution_count": null,
   "id": "7569025a",
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   "source": []
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