Created
December 26, 2015 14:53
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Simple merge sort
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#include <iostream> | |
#include <vector> | |
#include <set> | |
#include <map> | |
#include <algorithm> | |
#include <string> | |
using namespace std; | |
typedef long long ll; | |
typedef long double ld; | |
struct node { | |
int value; | |
node *next; | |
}; | |
void push_back(node *&root, int value) { | |
if (root) | |
push_back(root->next, value); | |
else | |
root = new node{value, nullptr}; | |
} | |
void push_front(node *&root, int value) { | |
root = new node{value, root}; | |
} | |
int len(node *root) { | |
if (root) | |
return len(root->next) + 1; | |
else | |
return 0; | |
} | |
node *split(node *root) { | |
int length = len(root); | |
node *cur = root; | |
for (int i = 0; i < length / 2 - 1; ++i) | |
cur = cur->next; | |
node *result = cur->next; | |
cur->next = nullptr; | |
return result; | |
} | |
node *merge(node *first, node *second) { | |
node dummy{0, nullptr}; | |
node *cur = &dummy; | |
while (first && second) { | |
node *best; | |
if (first->value < second->value) { | |
best = first; | |
first = first->next; | |
} else { | |
best = second; | |
second = second->next; | |
} | |
cur = cur->next = best; | |
} | |
cur->next = first ? first : second; | |
return dummy.next; | |
} | |
void sort(node *&list) { | |
if (!list || !list->next) | |
return; | |
node *rest = split(list); | |
sort(list); | |
sort(rest); | |
list = merge(list, rest); | |
} | |
int main() { | |
node *list = nullptr; | |
push_front(list, 1); | |
push_front(list, 2); | |
push_front(list, 3); | |
push_front(list, 4); | |
push_front(list, 5); | |
push_front(list, 4); | |
push_front(list, 5); | |
sort(list); | |
while (list) { | |
cout << list->value << " "; | |
list = list->next; | |
} | |
cout << endl; | |
return 0; | |
} |
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