YangKeao

#include <iostream>
#include <queue>
using namespace std;
int n,m,a,b,k;
int dist[150000];
bool inq[150000];
struct Edge{
	int u,v,c,next;
}edge[150000];
int e=0,head[150000];

YangKeao

#include <iostream>
using namespace std;
int a,b,c;
int t,g;
int father[6000];
int getfather(int a){
	if(father[a]==a) return a;
	else father[a]=getfather(father[a]);
	return father[a];
}

YangKeao

#include<stdio.h>
using namespace std;
long long q;
float CarmSqrt(float x){
    union{
        int intPart;
        float floatPart;
    } convertor;

YangKeao

#include <iostream>
using namespace std;
int n,c[1000000],m;
int t,g,l;
int low(int x){
	return x&(-x);
}
int sum(int x){
	int sum=0;
    while(x>0){

YangKeao

#include <stdio.h>
#include <iostream>
using namespace std;
struct Node
{
	long long left;
	long long right;
	long long delta;
	long long sum;
	Node *lc;

YangKeao

/*
	八数码难题 
*/
#include <iostream>
#include <cstdio>
using namespace std;
const int 
	d[4][2]={0,1, 
			0,-1, 
			1,0, 

YangKeao

#include<iostream>
#include<cstdio>
#include<ctype.h>
using namespace std;

inline int readint()
{
	char c=getchar();
	while(!isdigit(c))c=getchar();
	int x=0;

YangKeao

template <class T>
static void read(T &rec)
{
 	rec=0;
    char c;
    while((c=getchar())<'0' || c>'9');
    while(c>='0' && c<='9')
    {
    	rec=(rec<<3)+(rec<<1)+(c-'0');
        c=getchar();

YangKeao

//http://acm.hdu.edu.cn/showproblem.php?pid=1166
#include <iostream>
#include <stdio.h>
#include <string.h>
#define N 50005
using namespace std;

int M;
int T[N*4];
int Query(int s,int t){

YangKeao

#include <semaphore.h>
#include <random>

sem_t begin_sem1;
sem_t begin_sem2;
sem_t end_sem;

int X, Y;
int r1, r2;