def count_words_in_paragraph(paragraph):
# Convert paragraph to lowercase for case-insensitive counting
paragraph = paragraph.lower()
# Split paragraph into individual words
words = paragraph.split()
# Create an empty dictionary to store word counts
word_counts = {}
# Iterate through each word in the paragraph
for word in words:
# Remove leading and trailing punctuation from word
word = word.strip(".,!?")
# Skip empty words (occurs when there are multiple spaces between words)
if word == "":
continue
# Check if word already exists in word_counts dictionary
if word in word_counts:
# Increment the count of the word
word_counts[word] += 1
else:
# Add the word to the dictionary with an initial count of 1
word_counts[word] = 1
# Return the dictionary of word counts
return word_counts
# Get input from user
paragraph = input("Insert paragraph: ")
# Count the occurrences of each word in the paragraph
word_counts = count_words_in_paragraph(paragraph)
# Print the result
print(word_counts)
Associated Context | |
---|---|
Type | Code Snippet ( .py ) |
Associated Tags | Word counts Case-insensitive counting Word counting String manipulation User input Python function Dictionary creation Text processing Data analysis pandas Word Count Case-insensitive Split Paragraph Word Counts Dictionary Empty Words Increment Count Initial Count User Input Print Result |
💡 Smart Description | This code counts the number of occurrences in a given paragraph using lowercase for case-insensitive counting. It also creates an empty dictionary to store word counts, adds any leading and trailing punctuation from each word if there are multiple spaces between words The code snippet takes a paragraph as input from the user, converts it to lowercase, splits it into individual words, and counts the occurrences of each word. It then returns a dictionary with the word counts. |
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Related People | Jack Cheng, David Merwin |
Sensitive Information | No Sensitive Information Detected |
Shareable Link | https://davidmerwin.pieces.cloud/?p=3c9746a391 |