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def SubFib(startNumber, endNumber): | |
for cur in F(): | |
if cur > endNumber: return | |
if cur >= startNumber: | |
yield cur | |
for i in SubFib(10, 200): | |
print i |
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φ = (1+sqrt(5))/2 |
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def fib_iterative(n): | |
a, b = 0, 1 | |
while n > 0: | |
a, b = b, a + b | |
n -= 1 | |
return a |
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0, 1, 1, 2, 3, 5, 8, 13, 21, 34, ... |
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// |<--- p: F(n-1) - 1 --->| | |
// |<----- q ----->| |<-- r -->| | |
// +----+---+------+---+---------+ | |
// | | k | | m | | | |
// +----+---+------+---+---------+ |
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function fib(n) { | |
if (n <= 0) | |
return 0; | |
if (n <= 2) | |
return 1; | |
return fib(n-1) + fib(n-2); | |
} | |
function smallest_greater_eq_fib(n) { | |
let f = fib(0), |
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class Solution: | |
def fib(self, N: int) -> int: | |
if (N <= 1): | |
return N | |
A = [[1, 1], [1, 0]] | |
self.matrix_power(A, N-1) | |
return A[0][0] |
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function fib(n){ | |
if (n === 1) return 0; | |
if (n === 2) return 1; | |
return fib(n — 1) + fib(n — 2); | |
} |
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def fib_formula(n): | |
golden_ratio = (1 + math.sqrt(5)) / 2 | |
val = (golden_ratio**n - (1 - golden_ratio)**n) / math.sqrt(5) | |
return int(round(val)) |
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function * iterableObj() { | |
yield 'This'; | |
yield 'is'; | |
yield 'iterable.' | |
} | |
for (const val of iterableObj()) { | |
console.log(val); | |
} | |
// This | |
// is |