antonnifo
/ main.py
Created
January 19, 2019 08:45
Given two numbers X and Y, write a function that: 1 returns even numbers between X and Y, if X is greater than Y else it returns odd numbers between x and y For instance, take the integers 10 and 2 . the function would return all the even numbers between 2 and 10.
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| def number_game(x,y): | |
| if x > y: | |
| return [n for n in range(y,x) if n%2==0] | |
| elif y==x: | |
| return [] | |
| else: | |
| return [n for n in range(x,y) if n%2!=0] |
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| def myFunc(e): | |
| return len(e) | |
| states = ["Abia", "Adamawa", "Anambra", "Akwa Ibom", "Bauchi", "Bayelsa", "Benue", "Borno", | |
| "Cross River", "Delta", "Ebonyi", "Enugu", "Edo", "Ekiti", "Gombe", "Imo", "Jigawa", | |
| "Kaduna", "Kano", "Katsina", "Kebbi", "Kogi", "Kwara", "Lagos", "Nasarawa", "Niger", | |
| "Ogun", "Ondo", "Osun", "Oyo", "Plateau", "Rivers", "Sokoto", "Taraba", "Yobe", "Zamfara"] | |
| states.sort(reverse=True,key=myFunc) | |
| print(states[5]) |
antonnifo
/ number_to_ordinal.py
Created
October 25, 2018 11:20
This is a function that takes a number and return it as a string with the correct ordinal indicator suffix (in English). For example, 1 turns into "1st".
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| def numbertoordinal(number): | |
| number_string = str(number) | |
| SUFFIXES = {1: '1st', 2: '2nd', 3: '3rd'} | |
| # Checking for 11-14 because those are akward | |
| if int(number_string[-2:]) > 10 and int(number_string[-2:]) < 14: | |
| return number_string + 'th' | |
| else: | |
| suffix = SUFFIXES.get(int(number_string[-1:]), number_string + 'th') |
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