Asif Mehedi asifm

## index.html
<!DOCTYPE html>
<html lang="en">

<head>
    <meta charset="utf-8">
    <title>Top MSAs by new establishments</title>
    <script src="//d3js.org/d3.v3.min.js" charset="utf-8"></script>
    <style>
    body {
        margin: 0;

## index.html
<!DOCTYPE html>
<html lang="en">

<head>
    <meta charset="utf-8">
    <title>US Higher Education: Research Expenditure</title>
    <script src="//d3js.org/d3.v3.min.js" charset="utf-8"></script>
    <style type="text/css">
    body {
        margin: 50px;

## index.html
<!DOCTYPE html>
<html lang="en">

<head>
    <meta charset="utf-8">
    <title>United States: Albers Projection</title>
    <script type="text/javascript" src="//d3js.org/d3.v3.min.js"></script>
    <style type="text/css">

    .state {

## index.html
<!DOCTYPE html>
<html lang="en">

<head>
    <meta charset="utf-8">
    <title>UVa's out-of-state students later creating ventures in Virginia</title>
    <script src="//d3js.org/d3.v3.min.js" charset="utf-8"></script>
    <style>
    body {
        margin: 0;

## median.py
# The principle is to exhaustively compare all three numbers, so that we can know
# the order of the three numbers. We can do this with 3 levels of if statements.
# At first level we compare two of the three numbers (here a and b) and then
# at the next level we compare another pair (such as b and c or a and c). And then
# at the last level we compare the last remaining pair, if necessary. This way
# we exhaust all possibilities.


def median(a, b, c):
#    First compare the first two numbers a and b.

## .block
license: mit

## .block
license: gpl-3.0
height: 600

## .block
license: gpl-3.0
height: 600

## .block
license: mit

## .block
license: mit
height: 350
	<!DOCTYPE html>
	<html lang="en">

	<head>
	<meta charset="utf-8">
	<title>Top MSAs by new establishments</title>
	<script src="//d3js.org/d3.v3.min.js" charset="utf-8"></script>
	<style>
	body {
	margin: 0;
	# The principle is to exhaustively compare all three numbers, so that we can know
	# the order of the three numbers. We can do this with 3 levels of if statements.
	# At first level we compare two of the three numbers (here a and b) and then
	# at the next level we compare another pair (such as b and c or a and c). And then
	# at the last level we compare the last remaining pair, if necessary. This way
	# we exhaust all possibilities.


	def median(a, b, c):
	# First compare the first two numbers a and b.