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ISBN_978-4-7806-0852-6_Edition1_Printing4_p175_20_6.ipynb
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{
"nbformat": 4,
"nbformat_minor": 0,
"metadata": {
"colab": {
"name": " ISBN_978-4-7806-0852-6_Edition1_Printing4_p175_20_6.ipynb",
"provenance": [],
"authorship_tag": "ABX9TyNZ6lCjt2kaMR0vO3OntYVL",
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"kernelspec": {
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"<a href=\"https://colab.research.google.com/gist/axjack/c9e0274acab5760051eade6a0cabf4cc/-isbn_978-4-7806-0852-6_edition1_printing4_p175_20_6.ipynb\" target=\"_parent\"><img src=\"https://colab.research.google.com/assets/colab-badge.svg\" alt=\"Open In Colab\"/></a>"
]
},
{
"cell_type": "markdown",
"metadata": {
"id": "BNI_te9MmYU-"
},
"source": [
"# 書籍情報\n",
" - 『統計検定準1級対応 統計学実践ワークブック』 日本統計学会編,学術図書出版社\n",
" - 第1版第4刷\n",
" - p.175の式(20.6)\n",
"\n",
"# 問い合わせ箇所\n",
"式(20.6)\n",
"\n",
"$$\n",
"S_{[k]} = \\sum_{i=1}^N \\sum_{j=1}^2 (\\bar{y}_{[k]j} - \\bar{y} )^2 = \\frac{N}{4}(\\bar{y}_{[k]1} - \\bar{y}_{[k]2})^2\n",
"$$\n",
"\n",
"の真ん中の式から一番右の式は導出できない。\n",
"\n",
"# どうあるべきか\n",
"\n",
"$$\n",
"S_{[k]} = \\sum_{i=1}^{N/2} \\sum_{j=1}^2 (\\bar{y}_{[k]j} - \\bar{y} )^2 = \\frac{N}{4}(\\bar{y}_{[k]1} - \\bar{y}_{[k]2})^2\n",
"$$\n",
"\n",
"もしくは、\n",
"\n",
"$$\n",
"S_{[k]} = \\frac{1}{2}\\sum_{i=1}^{N} \\sum_{j=1}^2 (\\bar{y}_{[k]j} - \\bar{y} )^2 = \\frac{N}{4}(\\bar{y}_{[k]1} - \\bar{y}_{[k]2})^2\n",
"$$\n",
"\n",
"ではないかと考えます。\n",
"\n",
"# 問い合わせに至った理由\n",
"\n",
"応答 $ y_i $ の総平均を、\n",
"$$\\bar{y} = \\frac{1}{N}\\sum_{i=1}^N y_i \\tag{0}$$\n",
"\n",
"とし、以下が成り立つとする。\n",
"\n",
"$$\n",
" \\frac{N}{2} \\bar{y}_{[k]1} + \\frac{N}{2} \\bar{y}_{[k]2} = \\sum_{i=1}^N y_i \\tag{1}\n",
"$$\n",
"\n",
"このとき、\n",
"$$\n",
" \\frac{1}{2} \\Biggl( \\bar{y}_{[k]1} + \\bar{y}_{[k]2} \\Biggr) = \\frac{1}{N}\\sum_{i=1}^N y_i = \\bar{y} \\tag{2}\n",
"$$\n",
"\n",
"である。すると、p.175 (20.6)は、\n",
"\n",
"$$\n",
"\\begin{aligned}\n",
"S_{[k]} &= \\sum_{i=1}^N \\sum_{j=1}^2 (\\bar{y}_{[k]j} - \\bar{y} )^2 \\\\\n",
" &= \\sum_{i=1}^N \\Biggl[\n",
" (\\bar{y}_{[k]1} - \\bar{y} )^2 \n",
" +\n",
" (\\bar{y}_{[k]2} - \\bar{y} )^2 \n",
" \\Biggr]\\\\\n",
" &= \\sum_{i=1}^N \\Biggl[\n",
" (\\bar{y}_{[k]1} - \\frac{1}{2} \\Bigl( \\bar{y}_{[k]1} + \\bar{y}_{[k]2} \\Bigr) )^2 \n",
" +\n",
" (\\bar{y}_{[k]2} - \\frac{1}{2} \\Bigl( \\bar{y}_{[k]1} + \\bar{y}_{[k]2} \\Bigr) )^2 \n",
" \\Biggr]\\\\\n",
" &= \\sum_{i=1}^N \\Biggl[\n",
" (\\frac{1}{2} \\Bigl( \\bar{y}_{[k]1} - \\bar{y}_{[k]2} \\Bigr) )^2 \n",
" +\n",
" (-\\frac{1}{2} \\Bigl( \\bar{y}_{[k]1} - \\bar{y}_{[k]2} \\Bigr) )^2 \n",
" \\Biggr]\\\\\n",
" &= \\sum_{i=1}^N \\Biggl[\n",
" \\frac{2}{2^2} \\Bigl( \\bar{y}_{[k]1} - \\bar{y}_{[k]2} \\Bigr)^2 \\Biggr]\\\\\n",
" &= \n",
" \\frac{N}{2} \\Bigl( \\bar{y}_{[k]1} - \\bar{y}_{[k]2} \\Bigr)^2 \\\\\n",
"\\end{aligned}\n",
"$$\n",
"\n",
"となって、式(20.6)のようにイコールでは結べない、と考えました。\n",
"\n",
"以上。\n"
]
}
]
}
@axjack
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axjack commented Jan 6, 2022

問い合わせ結果

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