Can i wrap argc and argv to an object in C++?

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Can i wrap argc and argv to an object in C++?

Lets say you're a purist object oriented programmer and you want wrap the argc and argv constant variables in a more situable container like std::vector and don't know how?

Here is the pre-canned solution just for you (licensed under the WTFPL):

// File: ArgumentsList.hpp
typedef std::vector<std::string> ArgumentsList;

void fill_arguments(ArgumentsList &args, int argc, const char **argv)
{
    for (int i = 0; i < argc; i++)
        args[i] = std::string(argv[i]);
}

And use it like this:

#include "ArgumentsList.hpp"

void print_arguments(const ArgumentsList &arguments)
{
    for (int i = 0; i < arguments.size(); i++)
        std::cout << "arguments[" << i << "]: " << arguments[i] << std::endl;
}

int main(int argc, const char **argv)
{
    ArgumentsList arguments(argc);

    fill_arguments(arguments, argc, argv);

    print_arguments(arguments);

    return 0;
}