Show ANSI color sequences in a terminal

shell_colors

#!/usr/bin/env bash

# https://en.wikipedia.org/wiki/ANSI_escape_code


print_colors()
{
    # Print column headers.
    printf "%-4s    " '' ${bgs[@]}
    echo
    # Print rows.
    for bold in ${bolds[@]}; do
        for fg in ${fgs[@]}; do
            # Print row header
            printf "%s;%s  " $bold $fg
            # Print cells.
            for bg in ${bgs[@]}; do
                # Print cell.
                printf "\e[%s;%s;%sm%s\e[0m  " $bold $fg $bg " text "
            done
            echo
        done
    done
}

# Print standard colors.
bolds=( 0 1 )
fgs=( 3{0..7} )
bgs=( 4{0..7} )
print_colors

# Print vivid colors.
bolds=( 0 1 ) # Bold vivid is the same as bold normal.
fgs=( 9{0..7} )
bgs=( 10{0..7} )
print_colors

echo -e "0 \033[0mreset, normal\033[0m"
echo -e "1 \033[1mbold\033[0m"
echo -e "2 \033[2mfaint\033[0m"
echo -e "3 \033[3mitalic\033[0m"
echo -e "4 \033[4munderline\033[0m"
echo -e "5 \033[5mslow blink\033[0m"
echo -e "6 \033[6mrapid blink\033[0m"
echo -e "7 \033[7mreverse video\033[0m"
echo -e "8 \033[8mconceal\033[0m (conceal)"
echo -e "9 \033[9mcrossed-out\033[0m"