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June 25, 2018 11:53
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How to obtain all the values for the n-th root of a number using sympy
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"source": "How to obtain all the values for the $n$-th root of a number using sympy" | |
}, | |
{ | |
"metadata": { | |
"trusted": true | |
}, | |
"cell_type": "code", | |
"source": "from sympy import symbols, solve", | |
"execution_count": 1, | |
"outputs": [] | |
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"cell_type": "code", | |
"source": "x, y, n = symbols('x, y, n')", | |
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"outputs": [] | |
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"source": "z = x**n - y", | |
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"source": "roots = solve(z.subs({n: 5, y: 2}))\nroots", | |
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"execution_count": 4, | |
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"text/plain": "[2**(1/5),\n -2**(1/5)/4 + 2**(1/5)*sqrt(5)/4 - 2**(1/5)*I*sqrt(sqrt(5)/8 + 5/8),\n -2**(1/5)/4 + 2**(1/5)*sqrt(5)/4 + 2**(1/5)*I*sqrt(sqrt(5)/8 + 5/8),\n -2**(1/5)*sqrt(5)/4 - 2**(1/5)/4 - 2**(1/5)*I*sqrt(-sqrt(5)/8 + 5/8),\n -2**(1/5)*sqrt(5)/4 - 2**(1/5)/4 + 2**(1/5)*I*sqrt(-sqrt(5)/8 + 5/8)]" | |
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"metadata": { | |
"trusted": true | |
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"cell_type": "code", | |
"source": "froots = [r.evalf() for r in roots]\nfroots", | |
"execution_count": 5, | |
"outputs": [ | |
{ | |
"output_type": "execute_result", | |
"execution_count": 5, | |
"data": { | |
"text/plain": "[1.14869835499704,\n 0.35496731310463 - 1.09247705577745*I,\n 0.35496731310463 + 1.09247705577745*I,\n -0.929316490603148 - 0.675187952399881*I,\n -0.929316490603148 + 0.675187952399881*I]" | |
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