Bruce Bookman bbookman

## Info.plist
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<dict>
        <key>CFBundleDevelopmentRegion</key>
	<string>$(DEVELOPMENT_LANGUAGE)</string>
	<key>CFBundleExecutable</key>
	<string>$(EXECUTABLE_NAME)</string>
	<key>CFBundleIdentifier</key>
	<string>$(PRODUCT_BUNDLE_IDENTIFIER)</string>

## keybase.md

      
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                bbookman
                / keybase.md
            
            
              Created
              January 9, 2020 05:33
            
          
    Keybase proof

I hereby claim:

I am bbookman on github.
I am trentreznor (https://keybase.io/trentreznor) on keybase.
I have a public key ASAuct0Zg4DPo-WHmFXV3e47Xt9K7ZD2wnE-8ZKJauVCQAo

To claim this, I am signing this object:

  
## div7
'''
Find all of the numbers from 1-1000 that are divisible by 7
'''
div7 = [n for n in range(1,1000) if n % 7 == 0]
print(div7)

## consonants.py
'''
Create a list of all the consonants in the string "Yellow Yaks like yelling and yawning and yesturday they yodled while eating yuky yams"
'''
sentence = "Yellow Yaks like yelling and yawning and yesturday they yodled while eating yuky yams"

result = [letter for letter in sentence if letter not in 'a,e,i,o,u, " "']

## common_nums.py
'''
Find the common numbers in two lists (without using a tuple or set) list_a = [1, 2, 3, 4], list_b = [2, 3, 4, 5]

'''
list_a = [1, 2, 3, 4]
list_b = [2, 3, 4, 5]
common = [a for a in list_a if a in list_b]
print(common)

## even_odd.py
'''
Given numbers = range(20), produce a list containing the word 'even' if a number in the numbers is even, and the word 'odd' if the number is odd.  Result would look like ['odd','odd', 'even']

'''

result = ['even' if n%2 == 0 else 'odd' for n in range(20)]
print(result)

'''
Let's see the for loop and break out the syntax of the list comprehension

## common_tuples.py
'''
Produce a list of tuples consisting of only the matching numbers in these lists list_a = [1, 2, 3,4,5,6,7,8,9], list_b = [2, 7, 1, 12].  Result would look like (4,4), (12,12)
'''
list_a = [1, 2, 3,4,5,6,7,8,9]
list_b = [2, 7, 1, 12]

result = [(a, b) for a in list_a for b in list_b if a == b]
print(result)

## words_more_than_4.py
'''Find all of the words in a string that are less than 4 letters'''
sentence = 'On a summer day somner smith went simming in the sun and his red skin stung'

examine = sentence.split()

result = [word for word in examine if len(word) >=4]
print(result)

## findThree.py
'''
Find all of the numbers from 1-1000 that have a 3 in them
'''

three = [n for n in range(0,1000) if '3' in str(n)]
print(three)

## index_value.py
'''
 Get the index and the value as a tuple for items in the list ["hi", 4, 8.99, 'apple', ('t,b','n')].  Result would look like [(index, value), (index, value)]
 '''
items = ["hi", 4, 8.99, 'apple', ('t,b','n')]
result = [(index, item) for index, item in enumerate(items)]
print(result)
	<?xml version="1.0" encoding="UTF-8"?>
	<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
	<plist version="1.0">
	<dict>
	<key>CFBundleDevelopmentRegion</key>
	<string>$(DEVELOPMENT_LANGUAGE)</string>
	<key>CFBundleExecutable</key>
	<string>$(EXECUTABLE_NAME)</string>
	<key>CFBundleIdentifier</key>
	<string>$(PRODUCT_BUNDLE_IDENTIFIER)</string>
	'''
	Find all of the numbers from 1-1000 that are divisible by 7
	'''
	div7 = [n for n in range(1,1000) if n % 7 == 0]
	print(div7)
	'''
	Create a list of all the consonants in the string "Yellow Yaks like yelling and yawning and yesturday they yodled while eating yuky yams"
	'''
	sentence = "Yellow Yaks like yelling and yawning and yesturday they yodled while eating yuky yams"

	result = [letter for letter in sentence if letter not in 'a,e,i,o,u, " "']
	'''
	Find the common numbers in two lists (without using a tuple or set) list_a = [1, 2, 3, 4], list_b = [2, 3, 4, 5]

	'''
	list_a = [1, 2, 3, 4]
	list_b = [2, 3, 4, 5]
	common = [a for a in list_a if a in list_b]
	print(common)
	'''
	Given numbers = range(20), produce a list containing the word 'even' if a number in the numbers is even, and the word 'odd' if the number is odd. Result would look like ['odd','odd', 'even']

	'''

	result = ['even' if n%2 == 0 else 'odd' for n in range(20)]
	print(result)

	'''
	Let's see the for loop and break out the syntax of the list comprehension
	'''
	Produce a list of tuples consisting of only the matching numbers in these lists list_a = [1, 2, 3,4,5,6,7,8,9], list_b = [2, 7, 1, 12]. Result would look like (4,4), (12,12)
	'''
	list_a = [1, 2, 3,4,5,6,7,8,9]
	list_b = [2, 7, 1, 12]

	result = [(a, b) for a in list_a for b in list_b if a == b]
	print(result)
	'''Find all of the words in a string that are less than 4 letters'''
	sentence = 'On a summer day somner smith went simming in the sun and his red skin stung'

	examine = sentence.split()

	result = [word for word in examine if len(word) >=4]
	print(result)
	'''
	Find all of the numbers from 1-1000 that have a 3 in them
	'''

	three = [n for n in range(0,1000) if '3' in str(n)]
	print(three)
	'''
	Get the index and the value as a tuple for items in the list ["hi", 4, 8.99, 'apple', ('t,b','n')]. Result would look like [(index, value), (index, value)]
	'''
	items = ["hi", 4, 8.99, 'apple', ('t,b','n')]
	result = [(index, item) for index, item in enumerate(items)]
	print(result)