Skip to content

Instantly share code, notes, and snippets.

@bhuron
Created April 16, 2022 19:17
Show Gist options
  • Save bhuron/03b7dbc009a4b48cf2df48fc010dd3ff to your computer and use it in GitHub Desktop.
Save bhuron/03b7dbc009a4b48cf2df48fc010dd3ff to your computer and use it in GitHub Desktop.
iParcours 3e – Exercice 2 page 30
Display the source blob
Display the rendered blob
Raw
{
"cells": [
{
"metadata": {},
"cell_type": "markdown",
"source": "### Exercice 2 page 30\n\nLes programmes qui correspondent aux deux programmes de calcul d'Alice sont :\n"
},
{
"metadata": {
"trusted": false
},
"cell_type": "code",
"source": "def prog1(x):\n return pow(2 * x + 3, 2)\n\ndef prog2(x):\n return (pow(x, 2) * 4) + 12 * x + 9",
"execution_count": 2,
"outputs": []
},
{
"metadata": {},
"cell_type": "markdown",
"source": "En choisissant 3 comme nombre de départ, les deux programmes donnent\nle même résultat : 81"
},
{
"metadata": {
"trusted": false
},
"cell_type": "code",
"source": "prog1(3) == prog2(3) == 81",
"execution_count": 3,
"outputs": [
{
"data": {
"text/plain": "True"
},
"execution_count": 3,
"metadata": {},
"output_type": "execute_result"
}
]
},
{
"metadata": {},
"cell_type": "markdown",
"source": "Le premier programme est l'équivalent de $(2x + 3)^2$, \nle second de $4x^2 + 12x + 9$.\n\nTrouver le(s) nombre(s) choisi(s) par Alice ayant donné 9 comme résultat du deuxième\nprogramme revient à résoudre :\n\n\\begin{align*}\n4x^2 + 12x + 9 &= 9\\\\\n4x^2 + 12x &= 0\\\\\n4x(x + 3) &= 0\n\\end{align*}\n\nOr un produit de facteurs est nul si et seulement si un de ses facteurs au moins\nest nul.\n\nAinsi, on a :\n\\begin{align*}\n4x &= 0 \\qquad \\text{ou} \\qquad &x + 3 &= 0\\\\\n x &=0 &x &= -3\n\\end{align*}\n\nOn peut vérifier que ce sont les bonnes réponses."
},
{
"metadata": {
"trusted": false
},
"cell_type": "code",
"source": "prog2(0) == prog2(-3) == 9",
"execution_count": 6,
"outputs": [
{
"data": {
"text/plain": "True"
},
"execution_count": 6,
"metadata": {},
"output_type": "execute_result"
}
]
}
],
"metadata": {
"interpreter": {
"hash": "b0fa6594d8f4cbf19f97940f81e996739fb7646882a419484c72d19e05852a7e"
},
"kernelspec": {
"name": "python3",
"display_name": "Python 3 (ipykernel)",
"language": "python"
},
"language_info": {
"name": "python",
"version": "3.9.10",
"mimetype": "text/x-python",
"codemirror_mode": {
"name": "ipython",
"version": 3
},
"pygments_lexer": "ipython3",
"nbconvert_exporter": "python",
"file_extension": ".py"
},
"gist": {
"id": "",
"data": {
"description": "iParcours 3e – Exercice 2 page 30",
"public": true
}
}
},
"nbformat": 4,
"nbformat_minor": 2
}
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment