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iParcours 3ème Exercice 1 page 30
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"### Exercice 1 page 30\n", | |
"\n", | |
"On commence par coder les deux programmes de calcul. Il faut noter que le résultat du premier programme en fonction de x est l'équivalent de $(x - 3)²$.\n", | |
"Celui du second est $x² + 3x + 7$." | |
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"def progA(x):\n", | |
" return pow(x - 3, 2)\n", | |
"\n", | |
"def progB(x):\n", | |
" return pow(x, 2) + 3 * x + 7" | |
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"True" | |
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"progA(1) == 4" | |
] | |
}, | |
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"17" | |
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"source": [ | |
"progB(-5)" | |
] | |
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"On développe l'expression littérale correspondant au programme A.\n", | |
"\n", | |
"\\begin{align*}\n", | |
" A &= (x - 3)^2 \\\\\n", | |
" &= x^2 - 6x + 9\n", | |
"\\end{align*}\n", | |
"\n", | |
"Trouver un nombre de départ pour lequel les deux programmes donnent le même résultat\n", | |
"revient à résoudre :\n", | |
"\n", | |
"\\begin{align*}\n", | |
" x^2 - 6x + 9 &= x^2 + 3x + 7 \\\\\n", | |
" -6x - 3x &= 7 - 9 \\\\\n", | |
" -9x &= -2 \\\\\n", | |
" x &= \\frac{2}{9}\n", | |
"\\end{align*}\n", | |
"\n", | |
"On peut vérifier que c'est effectivement le cas." | |
] | |
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"True" | |
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}, | |
"execution_count": 5, | |
"metadata": {}, | |
"output_type": "execute_result" | |
} | |
], | |
"source": [ | |
"from fractions import Fraction\n", | |
"progA(Fraction(2, 9)) == progB(Fraction(2, 9))" | |
] | |
} | |
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