aws lambdaではてなのホッテントリのRSSを取得するpython

lambda_function.py

#coding: UTF-8

import json
import sys
import urllib.request
import xmltodict

def hotentry(category):
    url = "http://b.hatena.ne.jp/hotentry"
    
    if category=="all" or category=="":
        url += "?mode=rss"
    elif category=="social":
        url += "/social.rss"
    elif category=="it":
        url += "/it.rss"
    elif category=="life":
        url += "/life.rss"
    elif category=="knowledge":
        url += "/knowledge.rss"
    elif category=="fun":
        url += "/fun.rss"
    elif category=="entertainment":
        url += "/entertainment.rss"
    elif category=="game":
        url += "/game.rss"
    elif category=="economics":
        url += "/economics.rss"

    return url

def getCategory(event):
    category = ""
    
    if (isinstance(event, dict)):
        if ("queryStringParameters" in event):
            if ("category" in event["queryStringParameters"]):
                category = event["queryStringParameters"]["category"]

    return category

def lambda_handler(event, context):
    category = getCategory(event)
    url = hotentry(category)
    data = ""
    with urllib.request.urlopen(url) as res:
        xml = res.read().decode("utf-8")
        dict = xmltodict.parse(xml)
        data = json.dumps(dict, indent=4)

    return {
        "statusCode": "200",
        'headers': {
            'Content-Type': 'application/json',
            'Access-Control-Allow-Origin' : '*'
        },
        "body": data
    }