cbdavide

#!/bin/bash
re='^-?[0-9]+([.][0-9]+)?$'
if ! [[ $2 =~ $re ]] ; then
  echo "El parámetro inicial NO es un número."
  exit
fi

if ! [[ $3 =~ $re ]] ; then
  echo "El parámetro final NO es un número."
  exit

cbdavide

var binarySearch = function(array, value) {
    var guess,
        min = 0,
        max = array.length - 1;	

    while(min <= max){
        guess = Math.floor((min + max) /2);
	if(array[guess] === value)
	    return guess;
	else if(array[guess] < value)

cbdavide

var selectionSort = function(array) {
    var temp;

    for(var i=0; i<array.length; i++){
        var mi = i;
        
        for(var j = i + 1; j<array.length; j++) {
            if(array[j] < array[mi])
                mi = j;
        }

cbdavide

var merge_sort = function(array, b, e){
	
    if(b < e) {
        var m = Math.floor((b + e) / 2);
	//Recursive stuff
	merge_sort(array, b, m);
	merge_sort(array, m+1, e);
	//Merge stuff
	var lower = [],
        higher = [];

cbdavide

class Heap:

    def __init__(self, arr):
        self.cont = arr
        self.size = len(self.cont) - 1
        self.buildheap()

    def left(self, i):
        return (i << 1) + 1
    def right(self, i):

cbdavide

# Tree representation
class Node:
    def __init__(self, val):
        self.data = val
        self.right = None
        self.left = None

def recursive_inorder(node):
    if not node:
        return

cbdavide

typedef vector<int> vi;
/**
 * LONGEST INCREASING SUBSEQUENCE
 * COMPLEXITY O(N^2)
 */
int lci(vi &A) {
  vi DP (A.size(), 1);

  for(int i=1; i<(int)A.size(); i++) {    
    for(int j=0; j<i; j++) {

cbdavide

#include <cstdio>
using namespace std;

typedef long long ll;

/**
 * O(n)
 */
bool esPrimoLineal(ll n, ll &contador) {
	contador = 0LL;

cbdavide

from jinja2 import Template

with open('template.tpl') as file:
	text = file.read()

template = Template(text)

new = template.render(slide={'num': 1, 'name': 'a'})

with open('out', 'w') as output:

cbdavide

''''Maximum Subarray Problem - Extended Kadane
    Source: https://www.quora.com/How-do-I-solve-maximum-product-subarray-problems
'''
def max_product(A):

	maxG, maxC, minC = A[0], A[0], A[0]

	for num in A:
		temp = maxC
		maxC = max([num, temp * num, minC * num])