springmeyer

// See https://wiki.openstreetmap.org/wiki/Slippy_map_tilenames for more details.

var degrees2meters = function(lon,lat) {
        var x = lon * 20037508.34 / 180;
        var y = Math.log(Math.tan((90 + lat) * Math.PI / 360)) / (Math.PI / 180);
        y = y * 20037508.34 / 180;
        return [x, y]
}

x= -77.035974