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QUESTION 1
TIME: 10 minutes
Number is a palindrome if it is equal to the number with digits in reversed order. For example, 5, 44, 171, 4884 are palindromes and 43, 194, 4773 are not palindromes.

Write a method palindrome_chain_length which takes a positive number and returns the number of special steps needed to obtain a palindrome. The special step is: "reverse the digits, and add to the original number". If the resulting number is not a palindrome, repeat the procedure with the sum until the resulting number is a palindrome.

If the input number is already a palindrome, the number of steps is 0.
Input will always be a positive integer.
For example, start with 87:

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QUESTION 2
TIME: 5 minutes


What is the output of this line of code?
console.log((function x(n){return ((n > 1) ? n * x(n-2) : n)})(10));

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package com.codephillip.hello;

public class Main {

    public static void main(String[] args) {
        divider();
    }
}

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QUESTION 5
CREDIT: http://www.cs.unc.edu/~stotts/COMP204/refactor/chap1.html
TIME: 15 minutes

Refactor the following code

public class DomainObject {

    public DomainObject (String name)   {
        _name = name;

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QUESTION 4
TIME: 5 minutes


What will be the output of this code?

var x = 21;
var girl = function () {
    console.log(x);
    var x = 20;

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QUESTION 3
TIME: 5 minutes

Consider the following code. What will the output be, and why?

(function () {
    try {
        throw new Error();
    } catch (x) {
        var x = 1, y = 2;

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def download_invoice(self, request, pk=None):
    """
    Download Invoice Endpoint
    ---
    omit_serializer: True
    omit_parameters:
        - query
    """
    current_url = '{}?{}'.format(
        reverse(request.resolver_match.url_name, kwargs={'pk': pk}),

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private void parseXML(String targetFilePath) {
        try {
            FileInputStream is = new FileInputStream(targetFilePath);
            XmlToJson xmlToJson = new XmlToJson.Builder(is, null).build();
            JSONObject jsonObject = xmlToJson.toJson();
            
            Timber.d("Content " + jsonObject.toString());
            // get the root key.
            // This prevents us from manually checking key. This is a special case
            Iterator keys = jsonObject.keys();

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    private String getFileContent(String targetFilePath) {
        try {
            FileInputStream fis = new FileInputStream(targetFilePath);
            DataInputStream in = new DataInputStream(fis);
            BufferedReader br = new BufferedReader(new InputStreamReader(in));
            String strLine;
            StringBuilder sb = new StringBuilder();
            while ((strLine = br.readLine()) != null)
                sb.append(strLine);
            Timber.d("form data");

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/*
 * Copyright (C) 2009 University of Washington
 *
 * Licensed under the Apache License, Version 2.0 (the "License"); you may not use this file except
 * in compliance with the License. You may obtain a copy of the License at
 *
 * http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software distributed under the License
 * is distributed on an "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express