def rotate(matrix):
n = len(matrix)
# Reverse the rows
matrix.reverse()
# Transpose the matrix in-place# The original implementation has a time complexity of O(n), where n is the length of the input list nums.
# This is because each number in nums is checked against the set of seen numbers, which has an average time complexity of O(1) using hash-based set implementation.
# The implementation is already quite efficient, and there is not much room for performance improvement. However, we can make a small modification to potentially improve the average case performance.
# Revised implementation:
def contains_duplicate(nums):import java.util.HashMap;
public class MergeDictionaries {
public static HashMap<String, Integer> mergeDictionaries(HashMap<String, Integer> dict1, HashMap<String, Integer> dict2) {
HashMap<String, Integer> result = new HashMap<>(dict1);
for (String key : dict2.keySet()) {OlderNewer