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using System;

public class Program {
	private static void Main(string[] args) {
		int[] x = new int[10];
		if (x is uint[]) {
		    Console.WriteLine("x is uint");
		}
		object y = x;
		if (y is uint[]) {

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typedef char (&yes)[1];
typedef char (&no)[2];

template <typename B, typename D>
struct Host {
	operator B*() const;
	operator D*();
};

template <typename B, typename D>

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// Вырезка из набора простых boundary test cases парсера C++ комментариев
// 2003-2005 (ц) Руслан "aruslan" Абдикеев

// Константы
  std::cout << "C1. This is /* not a comment */\n";
  std::cout << "C2. This is // not a comment\n";
  std::cout << "C3. This is \" /* not a comment as well*/ \"\n";
  std::cout << "C4. This is \" // not a comment as well \"\n";
  std::cout << "C5. Let's print some random numbers: " << '/*' << '*/' << '\n';
  std::cout << "C6. Let's print a random number: " << '//' << '\n';

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#include <iostream>
using namespace std;

template <typename... T>
struct counter;

template <>
struct counter<> {
	static constexpr size_t count() {
		return 0;

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#include <stdio.h>
#include <stddef.h>
 
int main() {
	int a = 0;
	const size_t size = (size_t)((char*)(&a + 1) - (char*)(&a));
	printf("%x", size);
	return 0;
}

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#include <iostream>

struct A {};
struct B : virtual A {};
struct C {};
struct D : A, C {};
struct E;

int main() {
	std::cout << sizeof(void (A::*)()) << std::endl;

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/*
Задача такая: дано N чисел, N <= 100000, числа натуральные. Требуется: найти подмножество этих чисел, такое, что их сумма кратна N или сказать, что такого подмножества не существует.
Пример: 2 1 2 3. Ответ, например, [1,3] или [2,2] (c) mehas
*/

#include <iostream>
#include <vector>

using namespace std;

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// ---- original code

// when declaring this as const, FPS drops from 30fps to 4fps on NV. wat?
int T[8] = int[8](0x15,0x38,0x32,0x2c,0x0d,0x13,0x07,0x2a);

int b0(int N, int B) { return (N>>B) & 1; }
int b(ivec3 p, int B) {
    return T[b0(p.x,B)<<2 | b0(p.y,B)<<1 | b0(p.z,B)];
}

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sealed class StepProfiler
{
    private readonly Stopwatch _sw = new Stopwatch();
    private long _totalTime;
    private bool _started;

    public void Start()
    {
        Debug.Assert(!_started);
        Debug.Print("[!] Profiling started");

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# CoffeeScript port by David Bushong <david@bushong.net>
#
# Copyright 2012 Google Inc. All Rights Reserved.
#
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
#     http://www.apache.org/licenses/LICENSE-2.0
#