digitalex

java.math.BigInteger.new(java.lang.String.new("\x00\x00\x00\x00\x00\x00\x00\x10").getBytes()).longValue()

digitalex

grep -oP "Completed 200 OK in (\d+)ms" log/production.log | grep -oP "\d+"

# or, any request that spends at least 1ms on MassiveRecord:

cat log/production.log | grep -P "Completed 200 OK in (\d+)ms \(Views: \d+.\d+ms \| MassiveRecord: [1-9][0-9]?.\d+ms\)" | grep -oP "in \d+ms" | grep -oP "\d+" > ~/timings1.log

digitalex

nmap <D-Up> :tabnew<CR>
nmap <D-Right> :tabnext<CR>
nmap <D-Left> :tabprevious<CR>
nmap <D-Down> :tabclose<CR>

digitalex

sed -E '/^.$/d'

digitalex

find . -size 0k -exec rm {} \;

digitalex

def self.parse_ip(ip)
  ip.split('.').collect(&:to_i).inject { |memo,x| x + (memo << 0x1) }
end

digitalex

awk 'length($1) > length($2) {tmp = $2; $2 = $1; $1 = tmp} {print $0}' input.log > output.log

digitalex

-- Facebook puzzle #1 - Hors d'oeuvres
-- http://www.facebook.com/careers/puzzles.php?puzzle_id=7

output 0 = return ()
output x = 
	putStrLn (gethop x)
	output (x - 1)

gethop x
	| div3 x && div5 x = "Hop\n"