criterion.jpg

solution.ipynb

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    "<img src=\"criterion.jpg\" width=400>"
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       "[(0, 4, 2)]"
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   "source": [
    "def criteria1(x, y, z):\n",
    "    return x == 6 or y == 8 or z == 2\n",
    "\n",
    "def criteria2(x, y, z):\n",
    "    number = [6, 1, 4]\n",
    "    return ((x in number and x != number[0]) or\n",
    "            (y in number and y != number[1]) or\n",
    "            (z in number and z != number[2]))\n",
    "\n",
    "def criteria3(x, y, z):\n",
    "    number = [2, 0, 6]\n",
    "    return (((x in number) + (y in number) + (z in number)) == 2\n",
    "            and x != number[0]\n",
    "            and y != number[1]\n",
    "            and z != number[2])\n",
    "            \n",
    "def criteria4(x, y, z):\n",
    "    number = [7, 3, 8]\n",
    "    return x not in number and y not in number and z not in number\n",
    "            \n",
    "def criteria5(x, y, z):\n",
    "    number = [7, 8, 0]\n",
    "    return ((x in number and x != number[0]) or\n",
    "            (y in number and y != number[1]) or\n",
    "            (z in number and z != number[2]))\n",
    "            \n",
    "[(x, y, z)\n",
    " for x in range(0, 9)\n",
    " for y in range(0, 9)\n",
    " for z in range(0, 9)\n",
    " if all(f(x, y, z) for f in [criteria1, criteria2, criteria3, criteria4, criteria5])]"
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solution.py

# coding: utf-8

# <img src="criterion.jpg" width=400>

# In[1]:


def criteria1(x, y, z):
    return x == 6 or y == 8 or z == 2

def criteria2(x, y, z):
    number = [6, 1, 4]
    return ((x in number and x != number[0]) or
            (y in number and y != number[1]) or
            (z in number and z != number[2]))

def criteria3(x, y, z):
    number = [2, 0, 6]
    return (((x in number) + (y in number) + (z in number)) == 2
            and x != number[0]
            and y != number[1]
            and z != number[2])
            
def criteria4(x, y, z):
    number = [7, 3, 8]
    return x not in number and y not in number and z not in number
            
def criteria5(x, y, z):
    number = [7, 8, 0]
    return ((x in number and x != number[0]) or
            (y in number and y != number[1]) or
            (z in number and z != number[2]))
            
[(x, y, z)
 for x in range(0, 9)
 for y in range(0, 9)
 for z in range(0, 9)
 if all(f(x, y, z) for f in [criteria1, criteria2, criteria3, criteria4, criteria5])]