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Yi Lu eccstartup

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drwxr-xr-x 173 root root 28672 4月 10 10:02 ./
drwxr-xr-x 12 root root 4096 3月 30 11:13 ../
drwxr-xr-x 2 root root 4096 10月 17 03:00 accountsservice/
drwxr-xr-x 3 root root 4096 10月 17 03:01 aisleriot/
drwxr-xr-x 3 root root 4096 3月 30 10:37 apache2/
drwxr-xr-x 2 root root 4096 10月 17 03:01 apg/
drwxr-xr-x 2 root root 4096 3月 30 10:37 apr-util-1/
drwxr-xr-x 4 root root 4096 10月 17 02:59 apt/
drwxr-xr-x 2 root root 12288 10月 17 03:00 aspell/
drwxr-xr-x 2 root root 4096 3月 30 10:49 at-spi2-core/
/*
* robotMaze.js
*
* The blue key is inside a labyrinth, and extracting
* it will not be easy.
*
* It's a good thing that you're a AI expert, or
* we would have to leave empty-handed.
*/
/***************
* pointers.js *
***************
*
* You! How are you still alive?
*
* Well, no matter. Good luck getting through this
* maze of rooms - you'll never see me or the Algorithm again!
*/
/**********************
* superDrEvalBros.js *
**********************
*
* You're still here?! Well, Dr. Eval, let's see
* how well you can operate with one less dimension.
*
* Give up now. Unless you have a magic mushroom
* up your sleeve, it's all over.
*/
/*****************
* bossFight.js *
*****************
*
* NO FARTHER, DR. EVAL!!!!
* YOU WILL NOT GET OUT OF HERE ALIVE!!!!
* IT'S TIME YOU SEE MY TRUE FORM!!!!
* FACE MY ROBOT WRATH!!!!!
*/
-- http://www.4clojure.com/problem/148
sumone n a = div (a * (1 + c) * c) 2
where c = div (n - 1) a
sumtwo n a b = sumone n a + sumone n b - sumone n (a * b)
function spdiagm{T<:Integer}(B, d::Array{T, 1}, m::Integer, n::Integer)
ndiags = length(d)
ncoeffs = 0
for vec in B
ncoeffs += length(vec)
end
I = Array(T, ncoeffs)
J = Array(T, ncoeffs)
V = Array(Float64, ncoeffs)
id = 0

##Javascript

###1 嗯,关于执行 JS 的问题预习已经提到过了,确实是要打开 debug 窗口吧

这里 console.log(...) 可以理解成在打印 ... 的内容

其中 ... 可以是文字 "Hello" 也可以是整数 9

###2

##Javascript

###记录

首先,之前有人提到JS语言适合不适合入门?

其实……这个问题并不是太关键,毕竟这里已经接触过编程的人还是很多的

那么,大家的意见如何呢?