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Simple example of variational inference with autograd
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from autograd import grad, numpy as np | |
from autograd.scipy.stats import norm | |
from autograd.misc.optimizers import adam | |
def simple_vi(n=2000): | |
x = np.random.normal(loc=+1.5, scale=+0.3, size=10) | |
log_p = lambda z: np.mean(norm.logpdf(x[:, None], z[0], np.exp(z[1])), axis=0) | |
log_q = lambda z, l: norm.logpdf(z, l[:, None], 0.3) | |
samp_q = lambda l: np.random.normal(l[:, None], 0.3, (2, n)) | |
# https://arxiv.org/pdf/1401.0118.pdf, eq 3 | |
elbo = lambda l,z: log_q(z,l)*(log_p(z) - log_q(z,l)) | |
gelbo = elementwise_grad(elbo) | |
l = np.r_[0.1, 0.1] | |
g = grad(elbo) | |
for i in range(2000): | |
z = samp_q(l) | |
g = gelbo(l, z) | |
l += 0.01 * gelbo(l,z) / n | |
if i % 100 == 0: | |
print(l, g, np.sum(elbo(l,z))) | |
print('found', l[0], np.exp(l[1]), 'expected', 1.5, 0.3) | |
simple_vi() |
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import numpy as np | |
import sympy as sp | |
from autograd.misc.optimizers import adam | |
# helper to construct normal distribution | |
N = lambda x, mu, sig: sp.log((1/(sig*sp.sqrt(sp.pi*2)))*sp.exp((-1/2)*((x-mu)/sig)**2)).simplify() | |
# make vars & distributions | |
x, z, l = sp.symbols('x,z,l') | |
lp = N(x, z, 1/3) | |
lq = N(z, l, 1/3) | |
# variational objective & derivative | |
elbo = -(lq * (lp - lq)) | |
elbo_l = elbo.diff(l).simplify() | |
elbo_l_np = sp.lambdify([x,z,l], elbo_l) | |
# data and adam-compat function | |
x_ = np.random.randn()/3 + 1.5 | |
def loss(l, i): | |
z = np.random.normal(l, 1/3) | |
return elbo_l_np(x_, z, l) | |
# run and print result | |
lhat = adam(loss, 0.1, step_size=0.1, num_iters=1000) | |
print('found', lhat, 'expected', 1.5) |
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The BBVI paper proposes some variance reduction techniques (Rao Blackwellization + control variate) but they seem like tricks while this is sort of a core essence of VI.