fiqryq

const express = require("express");
const app = express();
const route = require("./Routes/index");
const port = 3000;

app.use("/", route);

app.listen(port, () => {
  console.log(`App runing at ${port}`);
});

fiqryq

var array = [1,2,3]
console.log(array)

fiqryq

const product = {
  data: [
    {
      name: "Indomie",
      price: 10000,
      stock: 15,
    },
    {
      name: "Telor Gulung",
      price: 5000,

fiqryq

const readline = require("readline");
const rl = readline.createInterface({
  input: process.stdin,
  output: process.stdout,
});

const question = (query) =>
  new Promise((resolve) => rl.question(query, resolve));

const tambah = (a, b) => {

fiqryq

// dectruct obj
const {
  rl,
  question,
  tambah,
  perkalian,
  pengurangan,
  pembagian,
} = require("./count");

fiqryq

const axios = require('axios');
const url = #URL_REST_API

axios.get(url)
  .then(function (response) {
    // handle success
    console.log(response);
  })
  .catch(function (error) {
    // handle error

fiqryq

 goToRevisionPage() {
    let url = this.router.serializeUrl(this.router.createUrlTree(['/extension-form'], { queryParams: { id: this.doctypeId, did: this.docid, revision: 1 } })
    );
    window.open(url, '_blank')
  }

fiqryq

let num1:number = 1
let num2:number = 2

const a = num1 < num2 ? 'red' : ( num1 > num2 ? 'blue' : 'green')
/** 
 * karena expresi pertama terpenuhi yaitu num1(1) < num2(2) akan bernilai true dan
 * program tidak akan mengeksekusi expresi selanjutnya karena expresi pertama terpenuhi
 * dan akan mencetak red di console. sedangkan jika expresi pertama tidak terpenuhi maka 
 * program akan mengeksekusi expresi selanjutnya.
 * */ 

fiqryq

let num1:number = 1
let num2:number = 2

const a = num1 < num2 ? 'red' : 'blue'
/** 
 * karena expresi pertama terpenuhi yaitu num1(1) < num2(2) akan bernilai true 
 * maka program akan mengeksekusi expresi kedua yaitu menampilkan red
 * */ 
console.log(a) 

fiqryq

expresi_satu ? expresi_dua : expresi_tiga