| import itertools | |
| """ | |
| The following math problem illustrates the essence of hacking: | |
| Use each of the numbers 1, 3, 4, and 6 exactly once with any of the four basic math operations (addition, subtraction, multiplication, and division) to total 24. Each number must be used once and only once, and you may define the order of operations; for example, 3 * (4 + 6) + 1 = 31 is valid, however incorrect, since it doesn’t total 24. | |
| The rules for this problem are well defined and simple, yet the answer eludes many. Like the solution to this problem (shown on the last page of this book), hacked solutions follow the rules of the system, but they use those rules in counterintuitive ways. | |
| """ | |
| nums = ['1','3','4','6'] |
| """ | |
| The Elves play this game by taking turns arranging the marbles in a circle | |
| according to very particular rules. The marbles are numbered starting with 0 | |
| and increasing by 1 until every marble has a number. | |
| First, the marble numbered 0 is placed in the circle. At this point, | |
| while it contains only a single marble, it is still a circle: | |
| the marble is both clockwise from itself and counter-clockwise from itself. | |
| This marble is designated the current marble. |
| // You can modify these | |
| const wordsToCheck = ["Apple", "red delisous", "orangg", "rgapefruit"]; | |
| const dictionary = ["apple", "banana", "orange", "grapefruit", "red delicious"]; | |
| // Don't modify below here | |
| const ALPHABET = "qwertyuiopasdfghjklzxcvbnm1234567890_ ".split("").sort(); | |
| const BASE_ALPHABET_HASH = ALPHABET.reduce((acc, x) => ({[x]: 0, ...acc}), {}); | |
| const DICTIONARY_HASHES = dictionary.map((w) => buildFreqHash(cleanStr(w))); |
Merkle tree to address: amount map
Select the key containing merkle proofs and amounts. to_entries[] returns objects on new lines instead of in an array, so wrap the statement in [()] to make it an array again. For each entry, map the amount to the address key. Merge back in to one big object with add.
jq '.recipients | [(to_entries[] | {(.key): .value.amount})] | add' results.json