MacTaylor hpcslag

## Gauß.js
function sum(number) {
    return (1 + number) * number / 2;
}

sum(1000);

## semantic-layout.html
<!DOCTYPE html>
<html>
<head>
    <meta charset="utf-8" />
    <title>Title</title>
    <link href="stylesheets/main.css" rel="stylesheet" />
</head>
<body>
    <header>
        <hgroup>

## gist:069e230fa8e23fe0ae933daf4cde086c

SELECT G.Home, G.Away,
       C1.CountryName, C2.CountryName

FROM Game G
JOIN Country C1 ON C1.CountryID = G.Home
JOIN Country C2 ON C2.CountryID = G.Away;

--http://stackoverflow.com/questions/4267929/whats-the-best-way-to-join-on-the-same-table-twice

## bigpipe.php
<?php set_time_limit(0); ?>
<!DOCTYPE html>
<html lang="zh-tw">
  <head>
    <meta charset="utf-8" />
    <title>BigPipe Demo</title>
  </head>
<body id="main">
    <div>
        Hello world

## mongodb.js
/*
* This is Official API Note, use mongojs!
*/
var mongojs = require('mongojs');

var db = mongojs('test',['table']); //test 是db的名稱，不需要create. table是集合的名稱

/**
* Search All(Find())
* @class

## index.ejs
<!DOCTYPE html>
<html>
<head>
	<meta charset="utf-8">
	<title>Hello World</title>
	<script type="text/javascript" src="./socket.io/socket.io.js" ></script>
	<script>
		var socket = io('http://localhost');
		socket.on('connect',function(){
			console.log("Hello World");

## microphone.js
	// success callback when requesting audio input stream
function gotStream(stream) {
    window.AudioContext = window.AudioContext || window.webkitAudioContext;
    var audioContext = new AudioContext();
    var analyser = audioContext.createAnalyser();//x

    // Create an AudioNode from the stream.
    var mediaStreamSource = audioContext.createMediaStreamSource( stream );

    // Connect it to the destination to hear yourself (or any other node for processing!)
	function sum(number) {
	return (1 + number) * number / 2;
	}

	sum(1000);
	<!DOCTYPE html>
	<html>
	<head>
	<meta charset="utf-8" />
	<title>Title</title>
	<link href="stylesheets/main.css" rel="stylesheet" />
	</head>
	<body>
	<header>
	<hgroup>

	SELECT G.Home, G.Away,
	C1.CountryName, C2.CountryName

	FROM Game G
	JOIN Country C1 ON C1.CountryID = G.Home
	JOIN Country C2 ON C2.CountryID = G.Away;

	--http://stackoverflow.com/questions/4267929/whats-the-best-way-to-join-on-the-same-table-twice
	<?php set_time_limit(0); ?>
	<!DOCTYPE html>
	<html lang="zh-tw">
	<head>
	<meta charset="utf-8" />
	<title>BigPipe Demo</title>
	</head>
	<body id="main">
	<div>
	Hello world
	/*
	* This is Official API Note, use mongojs!
	*/
	var mongojs = require('mongojs');

	var db = mongojs('test',['table']); //test 是db的名稱，不需要create. table是集合的名稱

	/**
	* Search All(Find())
	* @class
	// success callback when requesting audio input stream
	function gotStream(stream) {
	window.AudioContext = window.AudioContext \|\| window.webkitAudioContext;
	var audioContext = new AudioContext();
	var analyser = audioContext.createAnalyser();//x

	// Create an AudioNode from the stream.
	var mediaStreamSource = audioContext.createMediaStreamSource( stream );

	// Connect it to the destination to hear yourself (or any other node for processing!)