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import java.util.Arrays; | |
public class Solution { | |
public int solution(int[] A) { | |
Arrays.sort(A); | |
int l = A.length; | |
return A[l - 1] * A[l - 2] * A[l - 3]; | |
} | |
} |
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A non-empty zero-indexed array A consisting of N integers is given. The product of triplet (P, Q, R) equates to A[P] * A[Q] * A[R] (0 ≤ P < Q < R < N). | |
For example, array A such that: | |
A[0] = -3 | |
A[1] = 1 | |
A[2] = 2 | |
A[3] = -2 | |
A[4] = 5 | |
A[5] = 6 | |
contains the following example triplets: | |
(0, 1, 2), product is −3 * 1 * 2 = −6 |
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<RelativeLayout | |
android:layout_width="match_parent" | |
android:layout_height="match_parent"> | |
<ImageView | |
android:id="@+id/image" | |
android:layout_width="wrap_content" | |
android:layout_height="wrap_content" /> | |
<TextView | |
android:id="@+id/description" | |
android:layout_below="@id/image" |
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public class IsPermutation { | |
public int solution(int[] A) { | |
// Create a boolean array that will be used to store whether a number has been visited yet. | |
boolean[] counter = new boolean[A.length]; | |
// Loop throught each element in array A | |
for(int i = 0; i < A.length; i++) { | |
/* Does the number being visited fit between 1...N? Return 0 if it is beyond array bounds. | |
* e.g. [1, 2, 4] Clearly 3 is missing and this is not a permutation, this can be confirmed as | |
* 4 is grater than N, the length og the array. The order of the following IF statement is important; | |
* Not checking if a value is within bounds will cause an out of bounds error if it is. |
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A non-empty zero-indexed array A consisting of N integers is given. | |
A permutation is a sequence containing each element from 1 to N once, and only once. | |
For example, array A such that: | |
A[0] = 4 | |
A[1] = 1 | |
A[2] = 3 | |
A[3] = 2 | |
is a permutation, but array A such that: | |
A[0] = 4 | |
A[1] = 1 |
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public class LowestMissingInt { | |
public int solution(int[] A) { | |
// Create an array of booleans to represent if a number has been visited yet. | |
boolean[] counter = new boolean[A.length + 1]; | |
// Loop through setting each value as false. It has not been visited yet. | |
for(int i = 0; i < counter.length; i++) counter[i] = false; | |
// Loop through each value in the array, if the value is less than the length of A and greater than 0 | |
// It is a valid value, set it's value in counter, it is a 0 indexed array so subtract 1! | |
for(int a : A) if (a > 0 && a < counter.length) counter[a - 1] = true; | |
// Loop through the counter, if an element is false, return element index + 1 (it's a 0 index array!) |
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Write a function: | |
int solution(int A[], int N); | |
that, given a non-empty zero-indexed array A of N integers, returns the minimal positive integer that does not occur in A. | |
For example, given: | |
A[0] = 1 | |
A[1] = 3 | |
A[2] = 6 | |
A[3] = 4 | |
A[4] = 1 | |
A[5] = 2 |
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import java.util.Arrays; | |
/** | |
* Created by jordanterry on 26/10/14. | |
*/ | |
public class PermMissingElem { | |
public int Solution(int[] A) { | |
// If it is empty, return one, each permutation must start with 1 | |
if(A.length == 0) return 1; |
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A zero-indexed array A consisting of N different integers is given. The array contains integers in the range [1..(N + 1)], which means that exactly one element is missing. | |
Your goal is to find that missing element. | |
Write a function: | |
class Solution { public int solution(int[] A); } | |
that, given a zero-indexed array A, returns the value of the missing element. | |
For example, given array A such that: | |
A[0] = 2 | |
A[1] = 3 | |
A[2] = 1 | |
A[3] = 5 |
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A small frog wants to get to the other side of the road. The frog is currently located at position X and wants to get to a position greater than or equal to Y. The small frog always jumps a fixed distance, D. | |
Count the minimal number of jumps that the small frog must perform to reach its target. | |
Write a function: | |
class Solution { public int solution(int X, int Y, int D); } | |
that, given three integers X, Y and D, returns the minimal number of jumps from position X to a position equal to or greater than Y. | |
For example, given: | |
X = 10 | |
Y = 85 | |
D = 30 | |
the function should return 3, because the frog will be positioned as follows: |