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--[[ | |
Round Robin | |
Given 3 Teams (A, B, C), we want to organize a tournament schedule such that every team plays every other team exactly once. Here is a valid schedule for these 3 teams: | |
A - B | |
B - C | |
A - C | |
How about if we have N teams? Devise a general purpose algorithm that generates tournament schedules for N teams. | |
--]] |
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# Week 2 - Vim Buffer: I open up a new Vim buffer and type all the | |
# numbers 1 to 10,000, separated by spaces. Then, my cat walks on the keyboard | |
# and somehow activates a substitution command that replaces all the '0’ digits | |
# (zeros) with spaces. If I now sum up all the numbers in the buffer, as | |
# delineated by spaces, what is the total? | |
def vim_buffer(start = 1, limit) | |
(start..limit).flat_map { |num| num.to_s.gsub('0', ' ').split }.map(&:to_i).reduce(:+) | |
end |
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# From One End to the Other: Find the smallest possible | |
# (positive) integer that ends in a six such that if that six is removed and | |
# placed in front of the remaining digits of the number, the resulting number | |
# will be four times as large as the original. | |
i = 6 | |
loop do | |
digits = i.to_s.split('') | |
if digits.last == '6' && digits.rotate(-1).join.to_i == (i * 4) | |
puts i |
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-- Week 4: From One End to the Other: Find the smallest possible (positive) | |
-- integer that ends in a six such that if that six is removed and placed in front | |
-- of the remaining digits of the number, the resulting number will be four times | |
-- as large as the original. | |
function swap_first_and_last(t, n) | |
table.insert(t, 1, n) | |
return tonumber(table.concat(t)) | |
end |
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import Graphics.Element exposing (show) | |
import Array exposing (..) | |
import String exposing (..) | |
magicNumber : Array Int | |
magicNumber = | |
let | |
isNumber number = | |
String.right 1 (toString(number)) == "6" && | |
(String.append "6" (String.dropRight 1 (toString(number)))) |
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# LED Clock: You are (voluntarily) in a room that is completely dark except for | |
# the light coming from an old LED digital alarm clock. This is one of those | |
# clocks with 4 seven segment displays using an HH:MM time format. The clock is | |
# configured to display time in a 24 hour format and the leading digit will be | |
# blank if not used. What is the period of time between when the room is at its | |
# darkest to when it is at its lightest? | |
def compute_brightness(units) | |
cells_per_number = [ 6, 2, 5, 5, 4, 5, 6, 3, 7, 6 ] |
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{ | |
"spec/support/pages/*_page.rb": { | |
"command": "page", | |
"template": [ | |
"module Pages", | |
" class {camelcase|capitalize}Page < Page", | |
" end", | |
"end", | |
] | |
}, |
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{ | |
"lib/tilex_web/models": { | |
"type": "model" | |
}, | |
"lib/tilex_web/models/*.ex": { | |
"type": "model", | |
"alternate": "test/models/{}_test.exs", | |
"template": [ | |
"defmodule {project|camelcase|capitalize|basename}.{camelcase|capitalize|dot} do", | |
" use {project|camelcase|capitalize|basename}Web, :model", |
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{ | |
"client/app/actions/*.js": { | |
"command": "actions" | |
}, | |
"client/app/containers/*.js": { | |
"command": "container" | |
}, | |
"client/app/components/*.jsx": { | |
"command": "component" | |
}, |
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# Logrotater: | |
# - Daily | |
# - Timestamped | |
# - Doesn't error on missing log files | |
# - Keeps seven copies | |
# - Truncates log files (allows Rails to start writing to the new log file without | |
# a restart) | |
/var/app/current/log/production.log { | |
daily |
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