kenduigraha

let solution = (record) => {
  let answer = [];
  let userChat = [];

  for (let i = 0; i < record.length; i++) {
    let command = record[i].split(" ")[0];
    let userId = record[i].split(" ")[1];
    let nickName = record[i].split(" ")[2];
    let checkExistingUser = userChat
      .map((data, index) => (data.userId === userId ? index : ""))

kenduigraha

let solution = (n, users) => {
  let answer = [];
  let totalUsers = users.length;
  let countDuplicateStageUsers = users.reduce((prev, curr) => {
    prev[curr] = (prev[curr] || 0) + 1;
    return prev;
  }, {});

  // looping stages
  for (let i = 1; i <= n; i++) {

kenduigraha

let solution = (relation) => {
  let answer = 0;
  let dataRow = [];
  let findDuplicates = (arr) =>
    arr.filter((item, index) => arr.indexOf(item) != index);

  //   - Uniqueness: The relation does not have two distinct tuples
  //  (i.e. rows or records in common database language)
  //   with the same values for these attributes.
  for (let i = 0; i < relation[0].length; i++) {

kenduigraha

// switchWordByIndex
// return new string switched by index
const switchWordByIndex = (words, index, wordSwitched) => (words.substr(0, index) + wordSwitched + words.substr(index + 1));

// swapWordBasedOnIndex
// return new string swaped
const swapStringBasedOnIndex = (words, indexWord, indexComparedWord) => {
  // switch first word as temporary words
  const switchFirstWord = switchWordByIndex(words, indexWord, words[indexComparedWord]);
  // switch second word and get the result

kenduigraha

// Given an array of random characters with size n,
// String[] stringArr = ["A", "C", "K", "B" .....];
// write a procedure that will scan the array from the first element
// and print the first character that appear three times during scanning
const TOTAL_APPEAR = 3;

function scanArray(data) {
  let flag = 0;
  const result = []
  const dataLength = data.length;