kevinhowbrook

def calculate_m():
    # get a list of possible squared numbers, this give us the number of
    # rows and columns to use for the canvas, eg 4 = 2 x 2, 6 = 3 x 3...
    # Return: [] of squared numbers up to 10000 (hopefully we don't get that high!)
    m = []
    for i in range(1,10000):
        m.append(i*i)
    return(m)

def grid(n,m):

kevinhowbrook

for i,letter in enumerate(letters):
            # Only three numbers needed for RGB so use the first three values as a base
            # eg: [10, 4, 21]
            n = 255.0 / 26.0 # make sure we don't get a value above 255. (z = 26. 25 *10 = 260 but 26 * 9.8 = 248
            if i < 3:
                # add the first three values to a new list (number)
                letterPosition = alphabet.index(letter) * n # *n here to force a good large number base
                number.append(letterPosition)
            # Use the remaining values to fine tune the first three we have so it will be a better variant
            elif i >= 3 and i < 6: