kylelk

#include <stdio.h>
#include <string.h>

int main()
{
    // sha256 hash
    char *hash = "B94D27B9934D3E08A52E52D7DA7DABFAC484EFE37A5380EE9088F7ACE2EFCDE9";
    char *dividingChar = ":"; // The char to divide string
    int length=strlen(hash);
    int size = length+(length/3)+1; //size of final result

kylelk

#include <stdio.h>
#include <string.h>

struct Foo
{
	char *data;
	char *data2;
	int length;
};	
 int main()

kylelk

#include <stdio.h>
#define WIDTH 10

int main()
{
	int n;
    int count=0;
    printf("{");
	for (n = 0; n <99; n++)
	{

kylelk

Process:         eclipse [9939]
Path:            /Applications/adt-bundle-mac-x86_64-20131030/*/Eclipse.app/Contents/MacOS/eclipse
Identifier:      org.eclipse.eclipse
Version:         3.8 (3.8)
Code Type:       X86-64 (Native)
Parent Process:  launchd [243]
Responsible:     eclipse [9939]
User ID:         502

Date/Time:       2013-12-28 18:05:07.685 -0800

kylelk

import urllib, json, time

url = "http://blockchain.info/rawblock/"
hash = "0000000000000000d621e4c3182eb6015369fc156d5ce28e0b929da54d1c745a" 
for _ in range(20):
    r = urllib.urlopen(url+hash) 
    data = json.loads(r.read()) 
    index = str(data["block_index"])
    hash = str(data["prev_block"]) 
    open("chain/"+index+".txt", "w").write(str(data)) 

kylelk

#include <stdio.h>

int gcd( int a, int b ) {
    int result ;
    /* Compute Greatest Common Divisor using Euclid's Algorithm */
    __asm__ __volatile__ ( "movl %1, %%eax;"
                          "movl %2, %%ebx;"
                          "CONTD: cmpl $0, %%ebx;"
                          "je DONE;"
                          "xorl %%edx, %%edx;"

kylelk

def sha256(data):
    bytes = ""

    h0 = 0x6a09e667
    h1 = 0xbb67ae85
    h2 = 0x3c6ef372
    h3 = 0xa54ff53a
    h4 = 0x510e527f
    h5 = 0x9b05688c
    h6 = 0x1f83d9ab

kylelk
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kylelk

data=open(__file__).read() 
count = 0
for byte in data: 
    if count==8:
        print ""
        count=0
    print "&#x"+'{0:02X}'.format(ord(byte))+";",
    count+=1 

kylelk

1286b1ef093122af2f8dcbebfe9cba0e4e530e77