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View 股票挑选
# coding=utf-8
import requests
import time
import os
import json
import queue
import threading
import tushare as ts
View 淘宝店铺截图按键精灵脚本
// 从TXT文件中读取店铺名到数组
Dim shopNameFilePath="/sdcard/shopName.txt", shopNameArray
shopNameArray = File.ReadLines(shopNameFilePath)
// 截图保存路径
Dim snapShotPath = "/sdcard/shopPhoneDir/"
// 循环输入店铺名
For Each element In shopNameArray
View 全自动客户信息审核-按键精灵脚本
Function endFunction(path, number)
File.Write(path, number)
End Function
// 转账按钮界面的所有操作都包装在这个函数里
Function transfer(jpgStorePath, pngStorePath, path, number, itemNumber)
// 有没有头像的转账按钮位置不同,所以只能通过颜色来判断位置
Dim transferPointX, transferPointY
View 自动炒币脚本.py
# 日线
tradeDayLineURL = ""
tradeDayLineResponse =, headers=headers)
while tradeDayLineResponse.status_code!=200:
tradeDayLineResponse =, headers=headers)
dayContent = json.loads(tradeDayLineResponse.text)
dayListContent = list(dayContent)
dayLength = dayListContent.__len__()
# print(dayLength)
liuqinh2s / crossList.cpp
Created Dec 29, 2016
View crossList.cpp
#include <stdio.h>
#include <malloc.h>
struct NODE {
char data;
struct NODE *U;//
struct NODE *R;//
struct NODE *D;//
struct NODE *L;//
} *B,*q;
struct NODE *m[10];
liuqinh2s / ArrayInterface.cpp
Created Dec 27, 2016
数组的转换接口,比如我们经常要用到[[7,0],[4,4],[7,1],[5,0],[6,1],[5,2]],怎么把这一串字符串,传值给一个vector<pair<int, int>>& people;呢。这或许要用到字符串解析的代码,解析出来后还要一个一个传值,做轮子,不做白手起家的傻逼。
View ArrayInterface.cpp
void form_fun(string s, vector<pair<int, int>>& people){
if('[' &&'[' &&']' &&']'){
pair<int,int> p;
for(int i=0;i<s.size();i++){
while(i<s.size() && (>'9' ||<'0'))
if(i<s.size() &&<='9' &&>='0'){
string buffer="";
buffer +=;
while(i<s.size() &&<='9' &&>='0'){
View KMP.cpp
int KMP(Str str, Str substr, int next[]){
int i=0,j=0;
while(i<str.length && j<substr.length){
if(j==-1||[i] ==[j]){
View BSTree.cpp
template <class T>
class BSTree {
BSTNode<T> *mRoot;
// 前序遍历"二叉树"
liuqinh2s / BSNode.cpp
Last active Jun 11, 2016
View BSNode.cpp
template <class T>
class BSTNode{
T value;
BSTNode *left;
BSTNode *right;
BSTNode(T value1, BSTNode *l, BSTNode *r):
value(value1),left(l),right(r) {}
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