lufeihaidao

s = <<'EOF'
# copy from the source page
EOF
puts s.scan(/[a-z]/).join

lufeihaidao

# 我的代码，判断每个字符是否是字母
import re
astring = '''copy from the source page'''
bstring = ''
for a in astring:
if re.match('[a-zA-Z]',a):
    bstring = bstring+a

lufeihaidao

gets.tr "a-z", "c-zab"
# 就这么简单！然后输入字符串就好了！真让人喜欢！

lufeihaidao

import re, Image
im = Image.open("oxygen.png")
row = [im.getpixel((x, 47)) for x in range(0, im.size[0], 7)]
chrs = [chr(r) for r, g, b, a in row if r == g == b]
s = ''.join(chrs)
print ''.join(map(chr, map(int, re.findall(r'\d+',s))))

lufeihaidao

import xmlrpclib
xmlrpclib.ServerProxy('http://www.pythonchallenge.com/pc/phonebook.php').phone('Bert')

lufeihaidao

# 一定要注意，读写文件要强调是二进制
evil =  File.open("evil2.gfx", 'rb').read
outputs = (0..4).map { |i| File.open("out#{i}", "wb") }
evil.each_char.with_index { |c, i| outputs[i%5].write(c) }

lufeihaidao

raw = open('evil2.gfx','rb').read()
for i in range(5):
    open('out%d'%i, 'wb').write(raw[i::5])

lufeihaidao

require "RMagick"
img = Magick::ImageList.new 'cave.jpg'
r, c = img.rows, img.columns
for i in 0..r-2
  for j in 0..c-1
    if (i+j).odd?
      p = img.get_pixels(j, i+1, 1, 1)
      img.store_pixels(j, i, 1, 1, p)
    end
  end

lufeihaidao

from PIL import Image
img = Image.open("cave.jpg")
c,r = img.size
pix = img.load()
for j in range(r-1):
    for i in range(c):
        if (i+j)%2:
            pix[i,j] = pix[i,j+1]
img.show()
# 注意也可以用 img.getpixel 和 img.putpixel 来操作像素。

lufeihaidao

def f n
  n == 0 ? "1":
    f(n-1).scan(/(\d)(\1*)/).collect{|i| "#{i[1].size+1}#{i[0]}"}.join
end
puts f(30).size