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var vec:Vector.<int> = new <int>[ 1, 2, 3 ]; | |
var vec2:Vector.<int> = new <int>[ 3, 2, 1 ]; | |
var result:Vector.<int> = vec.concat(vec2); | |
trace(result); | |
// Outputs: 1,2,3,3,2,1 |
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var vec3:Vector.<int> = new <int>[ 9, 8, 7 ]; | |
result = vec.concat(vec2, vec3); | |
trace(result); | |
// Outputs: 1,2,3,3,2,1,9,8,7 |
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var arr:Array = [ 1, 2, 3 ]; | |
var result:Array = arr.concat(3, 2, 1); | |
trace(result); | |
// Outputs: 1,2,3,3,2,1 |
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var arr:Array = [ 1, 2, 3 ]; | |
var arr2:Array = [ 3, 2, 1 ]; | |
var result:Array = arr.concat(arr2, 4, 5, 6); | |
trace(result); | |
// Outputs: 1,2,3,3,2,1,4,5,6 |
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var vec:Vector.<int> = new <int>[ 1, 2, 3 ]; | |
var result:Vector.<int> = vec.concat(3, 2, 1); | |
trace(result); | |
// Unfortunately, this code ERRORS with: "Type Coercion failed" | |
// Cannot convert 3 to __AS3__.vec.Vector.<int>." |
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/** | |
* So, if I want to create a new Vector.<int> that | |
* appends 3, 2, 1 without modifying the original, | |
* I need to create *another* new Vector.<int>, just | |
* to pass the values to concat(). That's one extra | |
* Vector.<int> instantiation. Three total Vector.<int> | |
* objects, while only 2 should be needed: | |
* -- One, the original vec:Vector.<int>. | |
* -- Two, the new <int>[ 3, 2, 1 ] to pass the concat() | |
* parameter. |
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// We return -1 if val1 is first, 1 if val2 is first, and 0 | |
// if we don't care - just return a random value between | |
// -1 and 1 | |
function shuffle(val1:int, val2:int):int { | |
var random:int = Math.floor(Math.random() * 3) - 1; | |
return random; | |
} | |
var toSort:Array = [ 1, 2, 3, 4, 5 ]; | |
toSort.sort(shuffle); |
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var vec:Vector.<int> = new <int>[ 1, 2, 3, 4, 5 ]; | |
vec.sort(shuffle); | |
trace(vec); |
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var vec:Vector.<int> = new <int>[ 1, 2, 3, 4, 5 ]; | |
vec.sort(Array.DESCENDING); | |
trace(vec); | |
// Outputs: 5,4,3,2,1 |
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package { | |
public class MyObject { | |
public var alpha:String = ""; | |
public var val:int = 0; | |
public function MyObject(alpha:String, val:int) { | |
this.alpha = alpha; | |
this.val = val; | |
} | |