nimish

doSomething :: IO ()
doSomething = threadDelay 10000000

something1 :: IO ()
something1 = putStrLn "Something 1" >> threadDelay 10000000

something2 :: IO ()
something2 = putStrLn "Something 2" >> threadDelay 10000000

something3 :: IO ()

nimish

[python]
PipFlags=--proxy http://my.company's.proxy
DefaultInterpreter=python3
PipTool=pip3

nimish

DEBUG] Target alias resources has already been registered. Overwriting!
DEBUG] ProjectTree ignore_patterns: ['.*', '/dist/']
DEBUG] Parsing BUILD file BuildFile(src/python/BUILD, FileSystemProjectTree(/data/jenkins/temptest/pants-scipy-issue)).
DEBUG] Adding TargetAddressable(target_type=<class 'pants.backend.python.targets.python_requirement_library.PythonRequirementLibrary'>, name=numpy, **kwargs=...) to the BuildFileParser address map with BuildFileAddress(src/python/BUILD, numpy)
DEBUG] Adding TargetAddressable(target_type=<class 'pants.backend.python.targets.python_requirement_library.PythonRequirementLibrary'>, name=scipy, **kwargs=...) to the BuildFileParser address map with BuildFileAddress(src/python/BUILD, scipy)
DEBUG] Adding TargetAddressable(target_type=<class 'pants.backend.python.targets.python_binary.PythonBinary'>, name=example, **kwargs=...) to the BuildFileParser address map with BuildFileAddress(src/python/BUILD, example)
DEBUG] BuildFile(src/python/BUILD, FileSystemProjectTree(/data/jenki

nimish

Keybase proof

I hereby claim:

• I am nimish on github.
• I am nimish (https://keybase.io/nimish) on keybase.
• I have a public key ASCIsL2McG0f02gOXaolhqA8mFNlH4TtCtci03m8Ash-Tgo

To claim this, I am signing this object:

nimish

<?xml version="1.0" encoding="UTF-8">
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema">
	<xs:simpleType name="Extension">
		<xs:union memberTypes="Base Variant">
			<xs:simpleType>
				<xs:restriction base="xs:string">
					<xs:enumeration value="E"/>
					<xs:enumeration value="F"/>
				</xs:restriction>
			</xs:simpleType>

nimish

Moments from cumulants

IH moments are difficult to calculate explicitly, but the cumulants are easy. We can use the functional definition of the cumulant generating function to 'invert' back to the moments.

By definition, the moment generating function $M_X(t)$ of a random variable $X$ is: $$M_{X}(t) \equiv \mathop{\mathbb{E}}e^{tX}$$ and the cumulant generating function $C_X(t)$ is:

$$ C_{X}(t) \equiv \log M_{X}(t) = \log \mathop{\mathbb{E}}e^{tX} $$

This implies that: