total_cost.ipynb

{
 "cells": [
  {
   "cell_type": "code",
   "execution_count": 44,
   "metadata": {},
   "outputs": [],
   "source": [
    "def get_total_cost(costs, solution):\n",
    "    total_cost = 0\n",
    "    for i, row in enumerate(costs):\n",
    "        for j, cost in enumerate(row):\n",
    "            total_cost += cost * solution[i][j]\n",
    "    return total_cost"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 45,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[[30.  0.  0.  0.]\n",
      " [ 0.  0. 30. 40.]\n",
      " [10. 30. 10.  0.]]\n",
      "total cost:  680.0\n"
     ]
    }
   ],
   "source": [
    "costs = [\n",
    "    [ 2, 2, 2, 1],\n",
    "    [10, 8, 5, 4],\n",
    "    [ 7, 6, 6, 8]\n",
    "]\n",
    "supply = [30, 70, 50]\n",
    "demand = [40, 30, 40, 40]\n",
    "solution = transportation_simplex_method(supply, demand, costs)\n",
    "print(solution)\n",
    "print('total cost: ', get_total_cost(costs, solution))"
   ]
  }
 ],
 "metadata": {
  "kernelspec": {
   "display_name": "Python 3",
   "language": "python",
   "name": "python3"
  },
  "language_info": {
   "codemirror_mode": {
    "name": "ipython",
    "version": 3
   },
   "file_extension": ".py",
   "mimetype": "text/x-python",
   "name": "python",
   "nbconvert_exporter": "python",
   "pygments_lexer": "ipython3",
   "version": "3.6.5"
  }
 },
 "nbformat": 4,
 "nbformat_minor": 2
}