Gulp no-dependency spawn / execute a file with live stdout feedback

gulp-spawn.js

const gulp = require( 'gulp' );
const spawn = require( 'child_process' ).spawn;

/**
 * This solution to execute and watch a shell function from Gulp is
 * adapted from https://stackoverflow.com/a/10232330/3232832
 *
 * e.g. callSpawn( 'ping', [ '-c 5', 'google.com' ], cb );
 */
function callSpawn( command, arguments, cb ) {
  const call = spawn( command, arguments );

  // stdout
  call.stdout.on( 'data', function ( data ) {
    // like console.log, but without the trailing newline
    process.stdout.write( data.toString() );
  } );

  // stderr
  call.stderr.on( 'data', function ( data ) {
    console.log( data.toString() );

    cb( data.toString() );
  } );

  call.on( 'exit', function ( code ) {
    console.log( 'child process exited with code ' + code.toString() );

    cb();
  } );
}

gulp.task( 'test:ping', function ( cb ) {
  callSpawn( 'ping', [ '-c 10', 'google.com' ], cb );
} )