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@Robofied
Robofied / basic_python_csv3.py
Created February 5, 2019 10:26
## DictReader
with open('student_details2.csv' , 'r') as csv_file2:
## Reading csv file
## Here without delimiter specified
file2 = csv.DictReader(csv_file2, delimiter="t")
## Output is different as it uses t as raw form.
for line in file2:
print(line)
#[Output]:
@Robofied
Robofied / basic_python_student_details.csv
Created February 5, 2019 10:38
Name Roll no. Class
Akshay 1 2
Rajesh 24 3
Bram 12 6
Srishika 45 7
Radhika 78 6
Bluenix 67 6
@Robofied
Robofied / basic_python_student_details2.csv
Created February 5, 2019 10:39
We can make this file beautiful and searchable if this error is corrected: No commas found in this CSV file in line 0.
Name Roll no. Class
Akshay 1 2
Rajesh 24 3
Bram 12 6
Srishika 45 7
Radhika 78 6
Bluenix 67 6
@Robofied
Robofied / basic_python_error_handling1.py
Created February 5, 2019 10:47
## It is simply generating error with tracebacks
## Dividing by zero is undefined.
print(10/0)
## Generating a traceback
#[Output]:
#---------------------------------------------------------------------------
#ZeroDivisionError Traceback (most recent call last)
#<ipython-input-1-19547e02be0f> in <module>()
# 2 ## Dividing by zero is undefined.
@Robofied
Robofied / basic_python_error_handling2.py
Created February 5, 2019 10:48
## Using try and except block trying the above code of diving by zero.
try: a = 10/0
## It is simply generating an error in one line.
except Exception as e:
print(str(e))
#[Output]:
#division by zero
@Robofied
Robofied / basic_python_error_handling3.py
Created February 5, 2019 10:49
## Setting the variable to integer value in order to generate exception.
a= 7
if str(type(a)) == "<class 'int'>":
raise Exception('This variable cannot be integer')
#[Output]:
#-------------------------------------------------------------------------Exception: This variable cannot be integer
@Robofied
Robofied / basic_python_dictionary1.py
Created February 5, 2019 11:02
## Creating a dictionary
dict1 = {'one': 1, 'two': 2, 'three': 3}
print(dict1)
#[Output]:
#{'three': 3, 'one': 1, 'two': 2}
## How to access each element in dictionary
print(dict1['one'])
@Robofied
Robofied / basic_python_dictionary2.py
Last active February 5, 2019 11:28
## If key doesn't exist.
## It will generate a keyerror
print(dict1['four'])
#[Output]:
#---------------------------------------------------------------------------
#KeyError Traceback (most recent call last)
# in ()
# 1 ## It will generate a keyerror
# 2
@Robofied
Robofied / basic_python_dictionary3.py
Created February 5, 2019 11:14
## del() method
del dict1['one']
print(dict1)
#[Output]:
#{'three': 3, 'two': 2}
## pop() method
dict1.pop('two')
@Robofied
Robofied / basic_python_dictionary4.py
Created February 5, 2019 11:15
## How to declare ordered dictionary
from collections import OrderedDict
dict12 = OrderedDict()
dict12['one'] = 1
dict12['two'] = 2
dict12['three'] = 3
## It will print in a order of insertion.
print(dict12)
#[Output]: