Kazuya Sase sasekazu
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| <!DOCTYPE html> | |
| <html> | |
| <head> | |
| <meta charset="utf-8"> | |
| <title>audio test</title> | |
| <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script> | |
| <script> | |
| $(document).ready(function () { | |
| $("#puyon1Button").click(function () { |
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| /* | |
| * tbbTest.cpp | |
| * | |
| * Created on: 2014/11/05 | |
| * Author: sase | |
| */ | |
| #include <iostream> | |
| #include <math.h> | |
| #include <sys/time.h> |
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| /* | |
| * main.cu | |
| * | |
| * Created on: 2014/11/05 | |
| * Author: sase | |
| */ | |
| /* | |
| * tbbTest.cpp |
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| <!DOCTYPE html> | |
| <html> | |
| <head> | |
| <meta http-equiv="content-type" content="text/html; charset=UTF-8"> | |
| <meta charset="utf-8"> | |
| <title>logistic</title> | |
| <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script> | |
| <script type="text/javascript"> | |
| $(document).ready(function () { | |
| var canvas = document.getElementById('myCanvas'); |
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| <!DOCTYPE html> | |
| <html> | |
| <head> | |
| <meta http-equiv="content-type" content="text/html; charset=UTF-8"> | |
| <meta charset="utf-8"> | |
| <title>logistic</title> | |
| <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script> | |
| <script type="text/javascript"> | |
| $(document).ready(function () { |
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| #include <iostream> | |
| #include <fstream> | |
| #include <list> | |
| #include <math.h> | |
| #define N 2000 | |
| #define PI 3.141592 | |
| using namespace std; |
sasekazu
/ gist:a406c51adca34a37f2cc
Created
January 10, 2015 09:38
jacobi法による対角化 jacobi diagonalization
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| // jacobi法による実対称行列の対角化 | |
| // numeric.jsが必要 | |
| // 他の関数との依存性排除ver | |
| // size: 行列サイズ | |
| // intputA: 対角化される入力行列 ※対称行列でなければならない | |
| // 返り値 {DiagonalMatrix:A, OrthodonalMatrix:P}; | |
| // A(入力時) = P A(対角化後) P.transpose が成り立つ | |
| function jacobiDiagonalization(size, inputA, maxIteration, threshold) { | |
| var A=numeric.clone(inputA); |
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| // numeric.jsを使用 | |
| // データ点を配列で渡す 例: points = [[x0,y0],[x1,y1],[x2,y2],[x3,y3]]; | |
| // y=c[0]*x+c[1] で近似し係数cを配列で返す | |
| function leastSquare(points) { | |
| var A=numeric.rep([2, 2], 0); | |
| var b=numeric.rep([2], 0); | |
| for(var i=0; i<points.length; ++i) { | |
| A[0][0]+=points[i][0]*points[i][0]; | |
| A[0][1]+=points[i][0]; | |
| A[1][0]+=points[i][0]; |
sasekazu
/ gist:4e73c6baa7e568f47a1b
Last active
August 29, 2015 14:13
最小二乗法によるn次多項式の当てはめ least square
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| // numeric.jsを使用 | |
| // データ点を配列で渡す 例: points = [[x0,y0],[x1,y1],[x2,y2],[x3,y3]]; | |
| // 多項式の係数を配列で返す | |
| // dim=2 -> 直線 | |
| // dim=3 -> 二次曲線 | |
| function leastSquareN(points, dim) { | |
| if(points.length<dim) { | |
| return numeric.rep([dim], 0); | |
| } | |
| var A=numeric.rep([dim, dim], 0); |
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| // ラグランジュ補間（と等価な多項式補間） | |
| // 入力 N個の点列 points = [[x0,y0],[x1,x2],...,[xn-1,yn-1]] | |
| // 出力 多項式の係数配列c | |
| // y = c[0]*x^N-1 + c[1]*x^N-2 + ... + c[N-2]*x + c[N-1] | |
| function lagrangeInterpolation(points) { | |
| var dim=points.length; | |
| var A=numeric.rep([dim, dim], 0); | |
| var b=numeric.rep([dim], 0); | |
| for(var i=0; i<dim; ++i) { | |
| for(var j=0; j<dim; ++j) { |
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