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def find_duplicates(arr)
  arr \
    .group_by(&:itself)
    .map { |el, appearances| el if appearances.size > 1 }
    .compact
end

# Walkthrough:
# 1. [1,2,2,3,3,3].group_by(&:itself)
#    => { 1 => [1], 2 => [2,2], 3 => [3,3,3] }

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https://github.com/ekosz/postcard-sender
- Incorporated with React router
- Parent needs to know all fields children will use

https://gist.github.com/btholt/a5908e50eec2941ae6d7
- Does some light query consolidation (see `_.union(Plot.queries.movie(), Title.queries.movie(), Year.queries.movie())`)
- Doesn't use Flux, but I can see how it could be adapted

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You'll need to use the Vigenère table to calculate the encrypted text.

I'll walk through the encryption first; decryption just involves working backwards.

WARNING: There are spoilers below about the outcome of the Landsliders puzzle.

1. Write the phrase you want to encrypt:

WWWWHATHAPPENEDINLANDSLIDERSCOM

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function sayHello()
  print("hello world")
end