soimort

Keybase proof

I hereby claim:

• I am soimort on github.
• I am soimort (https://keybase.io/soimort) on keybase.
• I have a public key whose fingerprint is 8A9C A653 83B6 71BC 995C CEAE 07DA 00CB 7820 3251

To claim this, I am signing this object:

soimort

➜  build git:(master) make -C gmake config=release_x64
make: Entering directory `/home/soimort/Source/CppSharp/build/gmake'
==== Building CppSharp.AST (release_x64) ====
Creating ../lib/Release_x64
Creating ../obj/x64/Release/CppSharp.AST
==== Building CppSharp.Runtime (release_x64) ====
Creating ../obj/x64/Release/CppSharp.Runtime
==== Building CppSharp.CppParser (release_x64) ====
Creating ../obj/x64/Release/CppSharp.CppParser
AST.cpp

soimort

<?php

$file = file_get_contents($_GET['URL'], "r") or die("Error. File not found");
$lower = html_entity_decode(strstr($file, "</tr><tr"), ENT_QUOTES);
$line = (explode("</tr>", $lower));

echo "BEGIN:VCALENDAR\n";
echo "VERSION:2.0\n";
echo "PRODID:PHP\n";

soimort

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

void exor4(char *destination, const char *source1, const char *source2)
{
    *destination &= 0x0F;
    for (int i = 0; i < 4; i++)
        *destination |= (((*source1 >> (7 - i)) & 1) ^ ((*source2 >> (7 - i)) & 1)) << (7 - i);
    

soimort

print(3 * (999 // 3 + 1) * (999 // 3) // 2
    + 5 * (999 // 5 + 1) * (999 // 5) // 2
    - 15 * (999 // 15 + 1) * (999 // 15) // 2)

soimort

a, b, i, sum = 1, 2, 2, 0
while b <= 4000000:
    if b % 2 == 0:
        sum += b
    a, b, i = b, a + b, i + 1
print(sum)

soimort

n = 600851475143
while n % 2 == 0:
    n //= 2
i = 1
while n > 1:
    i += 2
    while n % i == 0:
        n //= i
print(i)

soimort

def gcd(a, b):
    if a:
        return gcd(b % a, a)
    else:
        return b
lcm = lambda a, b: a * b // gcd(a, b)
m = 1
for i in range(2, 21):
    m = lcm(m, i)
print(m)

soimort

for n in range(999, 99, -1):
    m = int(str(n) + str(n)[::-1])
    for i in range(999, 99, -1):
        if m % i == 0 and len(str(m // i)) == 3:
            print(m)
            exit()

soimort

print(((100 + 1) * 100 // 2) ** 2
    - sum([i ** 2 for i in range(1, 101)]))