tyler-austin

import arcpy

vector_file = os.path.join(r"/path/to/feature/class")

field_names = [f.name for f in arcpy.ListFields(vector_file)]

field_names
# [u'FID', u'Shape', u'Id']

tyler-austin

import arcpy
import os


def unique_values(vector_data, field):
    with arcpy.da.SearchCursor(vector_data, [field]) as cursor:
        return sorted({row[0] for row in cursor})


vector_data = os.path.join(r"/path/to/feature/class")

tyler-austin

import arcpy
import os


def _print_top_rows(vector_data, num_rows=10):
    field_names = [f.name for f in arcpy.ListFields(vector_data)]
    print field_names
    i_row = 0
    with arcpy.da.SearchCursor(vector_data, ['*']) as cursor:
        for row in cursor:

tyler-austin

import arcpy

def set_scratch_environment(self, scratch_dir, cpu_core):
	self.core_scratch_dir = os.path.join(scratch_dir, 'scratch_{0}'.format(cpu_core))
	os.mkdir(self.core_scratch_dir)
	arcpy.env.scratchWorkspace = self.core_scratch_dir
	arcpy.env.workspace = arcpy.env.scratchGDB
	self.scratch_gdb = os.path.join(self.core_scratch_dir, 'scratch.gdb')

tyler-austin

PUNCTUATION = '!"#$%&\'()*+,-./:;<=>?@[\\]^`{|}~'

def remove_punctuation(in_string):
    for punc in PUNCTUATION:
        in_string = in_string.replace(punc, '')
    return in_string

bad_string = 'I like (love) 2 make - life hard _ 4 my programmers #$AD!!!!'

bad_string = remove_punctuation(bad_string)

tyler-austin

After becoming famous, CodeBots decided to move to a new building and live together. The building is represented by a rectangular matrix of rooms, each cell containing an integer - the price of the room. Some rooms are free (their cost is 0), but that's probably because they are haunted, so all the bots are afraid of them. That is why any room that is free or is located anywhere below a free room in the same column is not considered suitable for the bots.

Help the bots calculate the total price of all the rooms that are suitable for them.

Example

For

matrix = [[0, 1, 1, 2], 
 [0, 5, 0, 0], 

tyler-austin

Given an array of strings, return another array containing all of its longest strings.

Example

For inputArray = ["aba", "aa", "ad", "vcd", "aba"], the output should be
allLongestStrings(inputArray) = ["aba", "vcd", "aba"].

Input/Output

• [time limit] 4000ms (py3)

tyler-austin

Given two strings, find the number of common characters between them.

Example

For s1 = "aabcc" and s2 = "adcaa", the output should be
commonCharacterCount(s1, s2) = 3.

Strings have 3 common characters - 2 "a"s and 1 "c".

Input/Output

tyler-austin

You have a string s that consists of English letters, punctuation marks, whitespace characters, and brackets. It is guaranteed that the parentheses in s form a regular bracket sequence.

Your task is to reverse the strings contained in each pair of matching parentheses, starting from the innermost pair. The results string should not contain any parentheses.

Example

For string s = "a(bc)de", the output should be
reverseParentheses(s) = "acbde".

Input/Output

tyler-austin

Several people are standing in a row and need to be divided into two teams. The first person goes into team 1, the second goes into team 2, the third goes into team 1 again, the fourth into team 2, and so on.

You are given an array of positive integers - the weights of the people. Return an array of two integers, where the first element is the total weight of team 1, and the second element is the total weight of team 2 after the division is complete.

Example

For a = [50, 60, 60, 45, 70], the output should be
alternatingSums(a) = [180, 105].

Input/Output