kn9ts

export default class UUID {
  constructor() {
    var d = new Date().getTime();
    var uuid = 'xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx'.replace(/[xy]/g, (c) => {
      var r = (d + Math.random() * 16) % 16 | 0;
      d = Math.floor(d / 16);
      return (c == 'x' ? r : (r & 0x3 | 0x8)).toString(16);
    });
    return uuid;
  }

vxhviet

Source: StackOverflow

This answer is a little late but I feel it'll be useful for future viewers. The dilemma seems to come from the ambiguity of the Android SearchView tutorial. The scenario they cover assumes you will be displaying the results in the same Activity the SearchView resides. In such a scenario, the Activity tag in the AndroidManifest.xml file would look something like this:

<activity
    android:name=".MainActivity"
    android:label="@string/main_activity_label"
    android:launchMode="singleTop">
        <intent-filter>

victorkifer

package com.username.ussd;
 
import android.app.Service;
import android.content.Intent;
import android.content.SharedPreferences;
import android.os.IBinder;
import android.os.RemoteException;
import android.preference.PreferenceManager;
import android.util.Log;
 

i-e-b

using System;
using System.Collections.Generic;
using System.Runtime.InteropServices;
using System.Diagnostics;
using System.Text;
using System.Threading;

namespace FileLockInfo
{
    public class Win32Processes

j4mie

400 or 403 for invalid form submission?

Conclusion: use 400

The Spec ( http://www.w3.org/Protocols/rfc2616/rfc2616-sec10.html )

10.4.1 400 Bad Request

The request could not be understood by the server due to malformed syntax. The client SHOULD NOT repeat the request without modifications.