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$.ajax({
    cache : false,
    type : "post",
    url : "cgi-bin/xxx.cgi",
    contentType : "application/x-www-form-urlencoded; charset=utf-8",
    dataType : "json",
    data : "act=xxx",
    success : function(result, textStatus) {
      // 成功
    },

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%.o:%.d
%.d:%.c
	@set -e; rm -f $@; \
	$(CC) -MM $(CPPFLAGS) $< > $@.$$$$; \
	sed 's,\($*\)\.o[ :]*,\1.o $@ : ,g' < $@.$$$$ > $@; \
	rm -f $@.$$$$

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# --numeric-owner:指定解压出来的文件所有者为root,因为目标为root(0)用于
tar --exclude="$(DIST_PAGKE)" --exclude=".svn" --exclude=".git" \
		--exclude="etc" \
		--exclude="data/config" \
		--exclude="*.log" \
		--exclude="scss" \
		--exclude=".project" --exclude=".gitignore" --exclude=".cproject" \
		-hczf $(DIST_PAGKE) -C $(DIST_DIR) . 	\
		--numeric-owner --owner=0 --group=0

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/* filename kargs.c 
* 来自:
* http://www.darkcoding.net/software/keyword-arguments-in-c/
* http://en.wikipedia.org/wiki/Named_parameter
*/
#include <stdio.h>  

/* 使用宏定义将关键字参数转换成为一个(匿名)结构体 */
/* 可以指定初始值:使用形如.x=101 */
#define draw_circle(...) draw_circle_func(   \

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// clog.h
#define DC_LOG_FD stderr ///<日志输出文件描述符,简单的输出到标准错误输出
#define CL_RED "\033[31m"
#define GREEN "\033[32m"
#define YELLOW "\033[33m"
#define BLUE "\033[34m"
#define PURPLE "\033[35m"
#define CL_ATTR_REV "\033[7m"
#define CL_ATTR_UNDERLINE "\033[4m"
#define _COLOR "\033[0m"

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// Use Gists to store code you would like to remember later on
console.log(window); // log the "window" object to the console

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#define swap(a, b) \
	do { typeof(a) __tmp = (a); (a) = (b); (b) = __tmp; } while (0)

/// 临时变量名字,
/// from http://stackoverflow.com/questions/3982348/implement-generic-swap-macro-in-c
#define swap(x, y) \
  do { typeof(x) temp##x##y = x; x = y; y = temp##x##y; } while (0)

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#define __same_type(a, b) __builtin_types_compatible_p(typeof(a), typeof(b))
#define BUILD_BUG_ON_ZERO(e) (sizeof(struct { int:-!!(e); }))
#define __must_be_array(a) BUILD_BUG_ON_ZERO(__same_type((a), &(a)[0]))
#define ARRAY_SIZE(arr) (sizeof(arr) / sizeof((arr)[0]) + __must_be_array(arr))

int a[10];
int *n =a;
ARRAY_SIZE(a);
ARRAY_SIZE(n); // compile error :)

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printf("%*.s",len,str);

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n*n矩阵逆时针题目
给定一个小于10的正数,从(0,0)点开始逆时针输出这个矩阵;
如:
1
01

5 //输入5,输出下面的矩阵
01 16 15 14 13
02 17 24 23 12
03 18 25 22 11