ztane

<?php
#Equivalent to this PHP codes:
$gmt_timezone = new DateTimeZone('GMT');
$obj_date = new DateTime(null,$gmt_timezone);
echo $obj_date->format('d/m/Y h:i:s');
#OR
date_default_timezone_set("GMT");
echo date('d/m/Y h:i:s', time());
?>

ztane

% python3 millionaire.py
Out of 1000000 cases
Initial was eliminated in 499869 cases (49.9869 %)
Initial was not eliminated in 500131 cases (50.0131 %)
There answer was different from initial in 249818 cases
Thus changing is winning 49.95051296560301 % if initial was not eliminated

ztane

import warnings
import inspect


NONE = object()

class TypingWarning(Warning):
    pass

ztane

%{
#include <stdio.h>
int line_num = 1;
%}

%%

"("     { printf("a opening parenthesis\n"); }
")"     { printf("a closing parenthesis\n"); }
[0-9]+  { printf("a number: %s\n", yytext); }

ztane

Keybase proof

I hereby claim:

• I am ztane on github.
• I am anttihaapala (https://keybase.io/anttihaapala) on keybase.
• I have a public key whose fingerprint is B811 2F0F ACC5 6F06 B79C 4E4D 69C6 71AF 0959 C672

To claim this, I am signing this object:

ztane

# advent of code helpers for Python 3

def input_file(filename='input'):
    """
    Read the input from current working directory,
    return as a string stripped
    """
    with open(input) as f:
        return f.read().strip()

ztane

(function ($) {
    function doSerializeArrayItems($current, target) {
        $current.children().each(function (i, e) {
            var $e = $(e),
                tmp;
            if (e.hasAttribute('data-form-item')) {
                var o = {};
                target.push(o);
                doSerialize($e, o);
            }

ztane

from collections import defaultdict
import time


i = 100
for _ in range(3):
    list_of_dictionaries = [{1: 1} for i in range(i)]
    list_of_dictionaries.append(dict.fromkeys(range(i)))

    n = sum(map(len, list_of_dictionaries))

ztane

int foo(int a, int b) {
    if ((a-b)==0) {
       return 1;
    }
    return 0;
}

int bar(int a, int b) {
    if (a==b) {
       return 1;

ztane

#include <stdio.h>

#define BUGGY

void funcA(int s, int g)
{
    int i, j = 0, k;
    int grp[4] = {-1, -1};

    for (i = 0, k = 0; i < 1; ++i)  {