send email in Python via SMTPLIB

gistfile1.py

import smtplib
import sys
import email.mime.text
mail_username='gmailUser@gmail.com'
mail_password='password'
from_addr = mail_username
to_addrs=('gmailUser@gmail.com')

HOST = 'smtp.gmail.com'
PORT = 25

# Create SMTP Object
smtp = smtplib.SMTP()
print 'connecting ...'

# show the debug log
smtp.set_debuglevel(1)

# connet
try:
    print smtp.connect(HOST,PORT)
except:
    print 'CONNECT ERROR ****'
# gmail uses ssl
smtp.starttls()
# login with username & password
try:
    print 'loginning ...'
    smtp.login(mail_username,mail_password)
except:
    print 'LOGIN ERROR ****'
# fill content with MIMEText's object
msg = email.mime.text.MIMEText('Hi ,All')
msg['From'] = from_addr
msg['To'] = ';'.join(to_addrs)
msg['Subject']='this is test msg'
print msg.as_string()
smtp.sendmail(from_addr,to_addrs,msg.as_string())
smtp.quit()

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It is completely open-source and privacy-focused (unlike Sendgrid, Postmark, Gmail, Proton Mail, Office 365, and others).

See their GitHub at @forwardemail