Rendezvous with Cassidoo Newsletter #311 - Interview Question of the Week

anagram.py

# Rendezvous with Cassidoo Newsletter #311 - Interview Question of the Week
# https://buttondown.email/cassidoo/archive/science-is-organized-knowledge-wisdom-is/

# Question:
# Given two strings s and t, return true if t is an anagram of s, and false otherwise. 
# Try this in a language you're not comfortable with! 

def is_anagram(word_1, word_2):
  # convert the words to lowercase, remove any spaces, and sort the characters
  # if the results match, word_2 is an anagram of word_1 (and vice versa)
  return sorted(word_1.lower().replace(' ', '')) == sorted(word_2.lower().replace(' ', ''))

# test examples from the newsletter
print(is_anagram('barbie', 'oppenheimer')) # Should output False
print(is_anagram('race', 'care')) # Should output True
print(is_anagram('anagram', 'nag a ram')) # Should output True